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molecular mass of 1-azido-1-deoxy-β-D-glucopyranoside tetraacetate

Input interpretation

1-azido-1-deoxy-β-D-glucopyranoside tetraacetate | molecular mass
1-azido-1-deoxy-β-D-glucopyranoside tetraacetate | molecular mass

Result

Find the molecular mass, m, for 1-azido-1-deoxy-β-D-glucopyranoside tetraacetate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_14H_19N_3O_9 Use the chemical formula, C_14H_19N_3O_9, to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 14  O (oxygen) | 9  N (nitrogen) | 3  H (hydrogen) | 19 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table:  | N_i | m_i/u  C (carbon) | 14 | 12.011  O (oxygen) | 9 | 15.999  N (nitrogen) | 3 | 14.007  H (hydrogen) | 19 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: |   | | N_i | m_i/u | mass/u  C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154  O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991  N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021  H (hydrogen) | 19 | 1.008 | 19 × 1.008 = 19.152  m = 168.154 u + 143.991 u + 42.021 u + 19.152 u = 373.318 u
Find the molecular mass, m, for 1-azido-1-deoxy-β-D-glucopyranoside tetraacetate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_14H_19N_3O_9 Use the chemical formula, C_14H_19N_3O_9, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 14 O (oxygen) | 9 N (nitrogen) | 3 H (hydrogen) | 19 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 14 | 12.011 O (oxygen) | 9 | 15.999 N (nitrogen) | 3 | 14.007 H (hydrogen) | 19 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 H (hydrogen) | 19 | 1.008 | 19 × 1.008 = 19.152 m = 168.154 u + 143.991 u + 42.021 u + 19.152 u = 373.318 u

Unit conversions

373.3 Da (daltons)
373.3 Da (daltons)
0.3733 kDa (kilodaltons)
0.3733 kDa (kilodaltons)
6.199×10^-22 grams
6.199×10^-22 grams
6.199×10^-25 kg (kilograms)
6.199×10^-25 kg (kilograms)
373.3 chemical atomic mass units  (unit officially deprecated)
373.3 chemical atomic mass units (unit officially deprecated)

Comparisons as mass of molecule

 ≈ 0.52 × molecular mass of fullerene ( ≈ 721 u )
≈ 0.52 × molecular mass of fullerene ( ≈ 721 u )
 ≈ 1.9 × molecular mass of caffeine ( ≈ 194 u )
≈ 1.9 × molecular mass of caffeine ( ≈ 194 u )
 ≈ 6.4 × molecular mass of sodium chloride ( ≈ 58 u )
≈ 6.4 × molecular mass of sodium chloride ( ≈ 58 u )

Corresponding quantities

Relative atomic mass A_r from A_r = m_aN_A/M_u:  | 373
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 373
Molar mass M from M = m_aN_A:  | 373 g/mol (grams per mole)
Molar mass M from M = m_aN_A: | 373 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u:  | 373
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 373
Molar mass M from M = m_mN_A:  | 373 g/mol (grams per mole)
Molar mass M from M = m_mN_A: | 373 g/mol (grams per mole)