Input interpretation
arsonium cation
Lewis structure
Draw the Lewis structure of arsonium cation. Start by drawing the overall structure of the molecule: Count the total valence electrons of the arsenic (n_As, val = 5) and hydrogen (n_H, val = 1) atoms, including the net charge: n_As, val + 4 n_H, val - n_charge = 8 Calculate the number of electrons needed to completely fill the valence shells for arsenic (n_As, full = 8) and hydrogen (n_H, full = 2): n_As, full + 4 n_H, full = 16 Subtracting these two numbers shows that 16 - 8 = 8 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 4 bonds and hence 8 bonding electrons in the diagram. Fill in the remaining unbonded electrons on each atom. In total, there remain 8 - 8 = 0 electrons left to draw. Lastly, fill in the formal charges: Answer: | |
General properties
formula | (AsH_4)^+ net ionic charge | +1 alternate names | arsanium | tetrahydridoarsenic | arsonium | arsonium(1+)
Other properties
ion class | arsenic(V) ions | cations | onium ions