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NH3 + Al = H2 + AlN

Input interpretation

NH_3 ammonia + Al aluminum ⟶ H_2 hydrogen + AlN aluminum nitride
NH_3 ammonia + Al aluminum ⟶ H_2 hydrogen + AlN aluminum nitride

Balanced equation

Balance the chemical equation algebraically: NH_3 + Al ⟶ H_2 + AlN Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NH_3 + c_2 Al ⟶ c_3 H_2 + c_4 AlN Set the number of atoms in the reactants equal to the number of atoms in the products for H, N and Al: H: | 3 c_1 = 2 c_3 N: | c_1 = c_4 Al: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 3/2 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 2 c_2 = 2 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 NH_3 + 2 Al ⟶ 3 H_2 + 2 AlN
Balance the chemical equation algebraically: NH_3 + Al ⟶ H_2 + AlN Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NH_3 + c_2 Al ⟶ c_3 H_2 + c_4 AlN Set the number of atoms in the reactants equal to the number of atoms in the products for H, N and Al: H: | 3 c_1 = 2 c_3 N: | c_1 = c_4 Al: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 3/2 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 2 c_2 = 2 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 NH_3 + 2 Al ⟶ 3 H_2 + 2 AlN

Structures

 + ⟶ +
+ ⟶ +

Names

ammonia + aluminum ⟶ hydrogen + aluminum nitride
ammonia + aluminum ⟶ hydrogen + aluminum nitride

Reaction thermodynamics

Enthalpy

 | ammonia | aluminum | hydrogen | aluminum nitride molecular enthalpy | -45.9 kJ/mol | 0 kJ/mol | 0 kJ/mol | -318 kJ/mol total enthalpy | -91.8 kJ/mol | 0 kJ/mol | 0 kJ/mol | -636 kJ/mol  | H_initial = -91.8 kJ/mol | | H_final = -636 kJ/mol |  ΔH_rxn^0 | -636 kJ/mol - -91.8 kJ/mol = -544.2 kJ/mol (exothermic) | | |
| ammonia | aluminum | hydrogen | aluminum nitride molecular enthalpy | -45.9 kJ/mol | 0 kJ/mol | 0 kJ/mol | -318 kJ/mol total enthalpy | -91.8 kJ/mol | 0 kJ/mol | 0 kJ/mol | -636 kJ/mol | H_initial = -91.8 kJ/mol | | H_final = -636 kJ/mol | ΔH_rxn^0 | -636 kJ/mol - -91.8 kJ/mol = -544.2 kJ/mol (exothermic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: NH_3 + Al ⟶ H_2 + AlN Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 NH_3 + 2 Al ⟶ 3 H_2 + 2 AlN Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_3 | 2 | -2 Al | 2 | -2 H_2 | 3 | 3 AlN | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NH_3 | 2 | -2 | ([NH3])^(-2) Al | 2 | -2 | ([Al])^(-2) H_2 | 3 | 3 | ([H2])^3 AlN | 2 | 2 | ([AlN])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([NH3])^(-2) ([Al])^(-2) ([H2])^3 ([AlN])^2 = (([H2])^3 ([AlN])^2)/(([NH3])^2 ([Al])^2)
Construct the equilibrium constant, K, expression for: NH_3 + Al ⟶ H_2 + AlN Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 NH_3 + 2 Al ⟶ 3 H_2 + 2 AlN Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_3 | 2 | -2 Al | 2 | -2 H_2 | 3 | 3 AlN | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NH_3 | 2 | -2 | ([NH3])^(-2) Al | 2 | -2 | ([Al])^(-2) H_2 | 3 | 3 | ([H2])^3 AlN | 2 | 2 | ([AlN])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NH3])^(-2) ([Al])^(-2) ([H2])^3 ([AlN])^2 = (([H2])^3 ([AlN])^2)/(([NH3])^2 ([Al])^2)

Rate of reaction

Construct the rate of reaction expression for: NH_3 + Al ⟶ H_2 + AlN Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 NH_3 + 2 Al ⟶ 3 H_2 + 2 AlN Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_3 | 2 | -2 Al | 2 | -2 H_2 | 3 | 3 AlN | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NH_3 | 2 | -2 | -1/2 (Δ[NH3])/(Δt) Al | 2 | -2 | -1/2 (Δ[Al])/(Δt) H_2 | 3 | 3 | 1/3 (Δ[H2])/(Δt) AlN | 2 | 2 | 1/2 (Δ[AlN])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/2 (Δ[NH3])/(Δt) = -1/2 (Δ[Al])/(Δt) = 1/3 (Δ[H2])/(Δt) = 1/2 (Δ[AlN])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: NH_3 + Al ⟶ H_2 + AlN Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 NH_3 + 2 Al ⟶ 3 H_2 + 2 AlN Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_3 | 2 | -2 Al | 2 | -2 H_2 | 3 | 3 AlN | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NH_3 | 2 | -2 | -1/2 (Δ[NH3])/(Δt) Al | 2 | -2 | -1/2 (Δ[Al])/(Δt) H_2 | 3 | 3 | 1/3 (Δ[H2])/(Δt) AlN | 2 | 2 | 1/2 (Δ[AlN])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[NH3])/(Δt) = -1/2 (Δ[Al])/(Δt) = 1/3 (Δ[H2])/(Δt) = 1/2 (Δ[AlN])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | ammonia | aluminum | hydrogen | aluminum nitride formula | NH_3 | Al | H_2 | AlN Hill formula | H_3N | Al | H_2 | AlN name | ammonia | aluminum | hydrogen | aluminum nitride IUPAC name | ammonia | aluminum | molecular hydrogen | nitriloalumane
| ammonia | aluminum | hydrogen | aluminum nitride formula | NH_3 | Al | H_2 | AlN Hill formula | H_3N | Al | H_2 | AlN name | ammonia | aluminum | hydrogen | aluminum nitride IUPAC name | ammonia | aluminum | molecular hydrogen | nitriloalumane

Substance properties

 | ammonia | aluminum | hydrogen | aluminum nitride molar mass | 17.031 g/mol | 26.9815385 g/mol | 2.016 g/mol | 40.989 g/mol phase | gas (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | -77.73 °C | 660.4 °C | -259.2 °C | 2200 °C boiling point | -33.33 °C | 2460 °C | -252.8 °C | 2517 °C density | 6.96×10^-4 g/cm^3 (at 25 °C) | 2.7 g/cm^3 | 8.99×10^-5 g/cm^3 (at 0 °C) | 3.26 g/cm^3 solubility in water | | insoluble | | decomposes surface tension | 0.0234 N/m | 0.817 N/m | |  dynamic viscosity | 1.009×10^-5 Pa s (at 25 °C) | 1.5×10^-4 Pa s (at 760 °C) | 8.9×10^-6 Pa s (at 25 °C) |  odor | | odorless | odorless |
| ammonia | aluminum | hydrogen | aluminum nitride molar mass | 17.031 g/mol | 26.9815385 g/mol | 2.016 g/mol | 40.989 g/mol phase | gas (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | -77.73 °C | 660.4 °C | -259.2 °C | 2200 °C boiling point | -33.33 °C | 2460 °C | -252.8 °C | 2517 °C density | 6.96×10^-4 g/cm^3 (at 25 °C) | 2.7 g/cm^3 | 8.99×10^-5 g/cm^3 (at 0 °C) | 3.26 g/cm^3 solubility in water | | insoluble | | decomposes surface tension | 0.0234 N/m | 0.817 N/m | | dynamic viscosity | 1.009×10^-5 Pa s (at 25 °C) | 1.5×10^-4 Pa s (at 760 °C) | 8.9×10^-6 Pa s (at 25 °C) | odor | | odorless | odorless |

Units