SO3 + Li2O = Li2SO4

SO_3 sulfur trioxide + Li_2O lithium oxide ⟶ Li_2SO_4 lithium sulfate

Balance the chemical equation algebraically: SO_3 + Li_2O ⟶ Li_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 SO_3 + c_2 Li_2O ⟶ c_3 Li_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for O, S and Li: O: | 3 c_1 + c_2 = 4 c_3 S: | c_1 = c_3 Li: | 2 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | SO_3 + Li_2O ⟶ Li_2SO_4

+ ⟶

sulfur trioxide + lithium oxide ⟶ lithium sulfate

Construct the equilibrium constant, K, expression for: SO_3 + Li_2O ⟶ Li_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: SO_3 + Li_2O ⟶ Li_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_3 | 1 | -1 Li_2O | 1 | -1 Li_2SO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression SO_3 | 1 | -1 | ([SO3])^(-1) Li_2O | 1 | -1 | ([Li2O])^(-1) Li_2SO_4 | 1 | 1 | [Li2SO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([SO3])^(-1) ([Li2O])^(-1) [Li2SO4] = ([Li2SO4])/([SO3] [Li2O])

Construct the rate of reaction expression for: SO_3 + Li_2O ⟶ Li_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: SO_3 + Li_2O ⟶ Li_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_3 | 1 | -1 Li_2O | 1 | -1 Li_2SO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term SO_3 | 1 | -1 | -(Δ[SO3])/(Δt) Li_2O | 1 | -1 | -(Δ[Li2O])/(Δt) Li_2SO_4 | 1 | 1 | (Δ[Li2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[SO3])/(Δt) = -(Δ[Li2O])/(Δt) = (Δ[Li2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| sulfur trioxide | lithium oxide | lithium sulfate formula | SO_3 | Li_2O | Li_2SO_4 Hill formula | O_3S | Li_2O | Li_2O_4S name | sulfur trioxide | lithium oxide | lithium sulfate IUPAC name | sulfur trioxide | dilithium oxygen(-2) anion | dilithium sulfate

| sulfur trioxide | lithium oxide | lithium sulfate molar mass | 80.06 g/mol | 29.9 g/mol | 109.9 g/mol phase | liquid (at STP) | | solid (at STP) melting point | 16.8 °C | | 845 °C boiling point | 44.7 °C | | 1377 °C density | 1.97 g/cm^3 | 2.013 g/cm^3 | 2.22 g/cm^3 solubility in water | reacts | | dynamic viscosity | 0.00159 Pa s (at 30 °C) | |