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molar mass of palladium(II) oxide hydrate

Input interpretation

palladium(II) oxide hydrate | molar mass
palladium(II) oxide hydrate | molar mass

Result

Find the molar mass, M, for palladium(II) oxide hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: OPd·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  H (hydrogen) | 2  O (oxygen) | 2  Pd (palladium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  H (hydrogen) | 2 | 1.008  O (oxygen) | 2 | 15.999  Pd (palladium) | 1 | 106.42 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016  O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998  Pd (palladium) | 1 | 106.42 | 1 × 106.42 = 106.42  M = 2.016 g/mol + 31.998 g/mol + 106.42 g/mol = 140.43 g/mol
Find the molar mass, M, for palladium(II) oxide hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: OPd·xH_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 2 O (oxygen) | 2 Pd (palladium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 2 | 1.008 O (oxygen) | 2 | 15.999 Pd (palladium) | 1 | 106.42 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 Pd (palladium) | 1 | 106.42 | 1 × 106.42 = 106.42 M = 2.016 g/mol + 31.998 g/mol + 106.42 g/mol = 140.43 g/mol

Unit conversion

0.14043 kg/mol (kilograms per mole)
0.14043 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.72 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.72 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 2.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 2.4 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 2.3×10^-22 grams  | 2.3×10^-25 kg (kilograms)  | 140 u (unified atomic mass units)  | 140 Da (daltons)
Mass of a molecule m from m = M/N_A: | 2.3×10^-22 grams | 2.3×10^-25 kg (kilograms) | 140 u (unified atomic mass units) | 140 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 140
Relative molecular mass M_r from M_r = M_u/M: | 140