H2S + Fe2O3 = H2O + S + FeS

hydrogen sulfide + iron(III) oxide ⟶ water + mixed sulfur + ferrous sulfide

Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, S, Fe and O: H: | 2 c_1 = 2 c_3 S: | c_1 = c_4 + c_5 Fe: | 2 c_2 = c_5 O: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 1 c_5 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 + ⟶ 3 + + 2

+ ⟶ + +

hydrogen sulfide + iron(III) oxide ⟶ water + mixed sulfur + ferrous sulfide

| hydrogen sulfide | iron(III) oxide | water | mixed sulfur | ferrous sulfide Hill formula | H_2S | Fe_2O_3 | H_2O | S | FeS name | hydrogen sulfide | iron(III) oxide | water | mixed sulfur | ferrous sulfide IUPAC name | hydrogen sulfide | | water | sulfur |