Input interpretation
![acetamide | molar mass](../image_source/ce492ac7d1cd35ea6c435b621b765706.png)
acetamide | molar mass
Result
![Find the molar mass, M, for acetamide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CONH_2 Use the chemical formula, CH_3CONH_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 2 H (hydrogen) | 5 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 2 | 12.011 H (hydrogen) | 5 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 2 | 12.011 | 2 × 12.011 = 24.022 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 24.022 g/mol + 5.040 g/mol + 14.007 g/mol + 15.999 g/mol = 59.068 g/mol](../image_source/145b5757dd92b176221641e3f48bc9a6.png)
Find the molar mass, M, for acetamide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CONH_2 Use the chemical formula, CH_3CONH_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 2 H (hydrogen) | 5 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 2 | 12.011 H (hydrogen) | 5 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 2 | 12.011 | 2 × 12.011 = 24.022 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 24.022 g/mol + 5.040 g/mol + 14.007 g/mol + 15.999 g/mol = 59.068 g/mol
Unit conversion
![0.05907 kg/mol (kilograms per mole)](../image_source/f41d171cf27a6932e2715861c2d37e08.png)
0.05907 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.082 ≈ 1/12 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/95d99b37f23a318ab0733d7142798a19.png)
≈ ( 0.082 ≈ 1/12 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.3 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/1c42f1b8a4afd575968bf611b4905a8b.png)
≈ 0.3 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.01 × molar mass of sodium chloride ( 58.443 g/mol )](../image_source/6df1ac52b035de3666d9c9d8193c7401.png)
≈ 1.01 × molar mass of sodium chloride ( 58.443 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 9.8×10^-23 grams | 9.8×10^-26 kg (kilograms) | 59 u (unified atomic mass units) | 59 Da (daltons)](../image_source/98bfa5831026eb7bee9b21c044e3f025.png)
Mass of a molecule m from m = M/N_A: | 9.8×10^-23 grams | 9.8×10^-26 kg (kilograms) | 59 u (unified atomic mass units) | 59 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 59](../image_source/5d3e7223c33a9ea33842b5026750090e.png)
Relative molecular mass M_r from M_r = M_u/M: | 59