Search

molar mass of ammonium nitrate

Input interpretation

ammonium nitrate | molar mass
ammonium nitrate | molar mass

Result

Find the molar mass, M, for ammonium nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NH_4NO_3 Use the chemical formula to count the number of atoms, N_i, for each element:  | number of atoms  H (hydrogen) | 4  N (nitrogen) | 2  O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | number of atoms | atomic mass/g·mol^(-1)  H (hydrogen) | 4 | 1.008  N (nitrogen) | 2 | 14.007  O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | number of atoms | atomic mass/g·mol^(-1) | mass/g·mol^(-1)  H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032  N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014  O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997  M = 4.032 g/mol + 28.014 g/mol + 47.997 g/mol = 80.043 g/mol
Find the molar mass, M, for ammonium nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NH_4NO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | number of atoms H (hydrogen) | 4 N (nitrogen) | 2 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | number of atoms | atomic mass/g·mol^(-1) H (hydrogen) | 4 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | number of atoms | atomic mass/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 4.032 g/mol + 28.014 g/mol + 47.997 g/mol = 80.043 g/mol

Unit conversion

0.08004 kg/mol (kilograms per mole)
0.08004 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.11 ≈ 1/9 ) × molar mass of fullerene (≈ 721 g/mol )
≈ ( 0.11 ≈ 1/9 ) × molar mass of fullerene (≈ 721 g/mol )
 ≈ 0.41 × molar mass of caffeine (≈ 194 g/mol )
≈ 0.41 × molar mass of caffeine (≈ 194 g/mol )
 ≈ 1.4 × molar mass of sodium chloride (≈ 58 g/mol )
≈ 1.4 × molar mass of sodium chloride (≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 1.3×10^-22 grams  | 1.3×10^-25 kg (kilograms)  | 80 u (unified atomic mass units)  | 80 Da (daltons)
Mass of a molecule m from m = M/N_A: | 1.3×10^-22 grams | 1.3×10^-25 kg (kilograms) | 80 u (unified atomic mass units) | 80 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 80
Relative molecular mass M_r from M_r = M_u/M: | 80