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mass fractions of manganese(II) sulfate

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manganese(II) sulfate | elemental composition
manganese(II) sulfate | elemental composition

Result

Find the elemental composition for manganese(II) sulfate in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: MnSO_4 Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule:  | number of atoms  Mn (manganese) | 1  O (oxygen) | 4  S (sulfur) | 1  N_atoms = 1 + 4 + 1 = 6 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work:  | number of atoms | atom fraction  Mn (manganese) | 1 | 1/6  O (oxygen) | 4 | 4/6  S (sulfur) | 1 | 1/6 Check: 1/6 + 4/6 + 1/6 = 1 Compute atom percents using the atom fractions:  | number of atoms | atom percent  Mn (manganese) | 1 | 1/6 × 100% = 16.7%  O (oxygen) | 4 | 4/6 × 100% = 66.7%  S (sulfur) | 1 | 1/6 × 100% = 16.7% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table:  | number of atoms | atom percent | atomic mass/u  Mn (manganese) | 1 | 16.7% | 54.938044  O (oxygen) | 4 | 66.7% | 15.999  S (sulfur) | 1 | 16.7% | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m:  | number of atoms | atom percent | atomic mass/u | mass/u  Mn (manganese) | 1 | 16.7% | 54.938044 | 1 × 54.938044 = 54.938044  O (oxygen) | 4 | 66.7% | 15.999 | 4 × 15.999 = 63.996  S (sulfur) | 1 | 16.7% | 32.06 | 1 × 32.06 = 32.06  m = 54.938044 u + 63.996 u + 32.06 u = 150.994044 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work:  | number of atoms | atom percent | mass fraction  Mn (manganese) | 1 | 16.7% | 54.938044/150.994044  O (oxygen) | 4 | 66.7% | 63.996/150.994044  S (sulfur) | 1 | 16.7% | 32.06/150.994044 Check: 54.938044/150.994044 + 63.996/150.994044 + 32.06/150.994044 = 1 Compute mass percents using the mass fractions: Answer: |   | | number of atoms | atom percent | mass percent  Mn (manganese) | 1 | 16.7% | 54.938044/150.994044 × 100% = 36.38%  O (oxygen) | 4 | 66.7% | 63.996/150.994044 × 100% = 42.38%  S (sulfur) | 1 | 16.7% | 32.06/150.994044 × 100% = 21.23%
Find the elemental composition for manganese(II) sulfate in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: MnSO_4 Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms Mn (manganese) | 1 O (oxygen) | 4 S (sulfur) | 1 N_atoms = 1 + 4 + 1 = 6 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction Mn (manganese) | 1 | 1/6 O (oxygen) | 4 | 4/6 S (sulfur) | 1 | 1/6 Check: 1/6 + 4/6 + 1/6 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent Mn (manganese) | 1 | 1/6 × 100% = 16.7% O (oxygen) | 4 | 4/6 × 100% = 66.7% S (sulfur) | 1 | 1/6 × 100% = 16.7% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u Mn (manganese) | 1 | 16.7% | 54.938044 O (oxygen) | 4 | 66.7% | 15.999 S (sulfur) | 1 | 16.7% | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u Mn (manganese) | 1 | 16.7% | 54.938044 | 1 × 54.938044 = 54.938044 O (oxygen) | 4 | 66.7% | 15.999 | 4 × 15.999 = 63.996 S (sulfur) | 1 | 16.7% | 32.06 | 1 × 32.06 = 32.06 m = 54.938044 u + 63.996 u + 32.06 u = 150.994044 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction Mn (manganese) | 1 | 16.7% | 54.938044/150.994044 O (oxygen) | 4 | 66.7% | 63.996/150.994044 S (sulfur) | 1 | 16.7% | 32.06/150.994044 Check: 54.938044/150.994044 + 63.996/150.994044 + 32.06/150.994044 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent Mn (manganese) | 1 | 16.7% | 54.938044/150.994044 × 100% = 36.38% O (oxygen) | 4 | 66.7% | 63.996/150.994044 × 100% = 42.38% S (sulfur) | 1 | 16.7% | 32.06/150.994044 × 100% = 21.23%

Mass fraction pie chart

Mass fraction pie chart
Mass fraction pie chart