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molar mass of calcium selenate dihydrate

Input interpretation

calcium selenate dihydrate | molar mass
calcium selenate dihydrate | molar mass

Result

Find the molar mass, M, for calcium selenate dihydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CaSeO_4·2H_2O Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Ca (calcium) | 1  H (hydrogen) | 4  O (oxygen) | 6  Se (selenium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Ca (calcium) | 1 | 40.078  H (hydrogen) | 4 | 1.008  O (oxygen) | 6 | 15.999  Se (selenium) | 1 | 78.971 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Ca (calcium) | 1 | 40.078 | 1 × 40.078 = 40.078  H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032  O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994  Se (selenium) | 1 | 78.971 | 1 × 78.971 = 78.971  M = 40.078 g/mol + 4.032 g/mol + 95.994 g/mol + 78.971 g/mol = 219.075 g/mol
Find the molar mass, M, for calcium selenate dihydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CaSeO_4·2H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ca (calcium) | 1 H (hydrogen) | 4 O (oxygen) | 6 Se (selenium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ca (calcium) | 1 | 40.078 H (hydrogen) | 4 | 1.008 O (oxygen) | 6 | 15.999 Se (selenium) | 1 | 78.971 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ca (calcium) | 1 | 40.078 | 1 × 40.078 = 40.078 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 Se (selenium) | 1 | 78.971 | 1 × 78.971 = 78.971 M = 40.078 g/mol + 4.032 g/mol + 95.994 g/mol + 78.971 g/mol = 219.075 g/mol

Unit conversion

0.21907 kg/mol (kilograms per mole)
0.21907 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 3.6×10^-22 grams  | 3.6×10^-25 kg (kilograms)  | 219 u (unified atomic mass units)  | 219 Da (daltons)
Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 219 u (unified atomic mass units) | 219 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 219
Relative molecular mass M_r from M_r = M_u/M: | 219