Input interpretation
beryllium hydride | molar mass
Result
Find the molar mass, M, for beryllium hydride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BeH_2 Use the chemical formula, BeH_2, to count the number of atoms, N_i, for each element: | N_i Be (beryllium) | 1 H (hydrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Be (beryllium) | 1 | 9.0121831 H (hydrogen) | 2 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Be (beryllium) | 1 | 9.0121831 | 1 × 9.0121831 = 9.0121831 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 M = 9.0121831 g/mol + 2.016 g/mol = 11.028 g/mol
Unit conversion
0.011028 kg/mol (kilograms per mole)
Comparisons
≈ ( 0.19 ≈ 1/5 ) × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 0.61 × molar mass of water ( ≈ 18 g/mol )
≈ 0.92 × carbon-12 molar mass ( ≈ 0.012 kg/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1.8×10^-23 grams | 1.8×10^-26 kg (kilograms) | 11 u (unified atomic mass units) | 11 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 11