Search

I2 + Na2CO3 + C2H5OH = NaI + H2CO3 + CHI3 + HCOONa

Input interpretation

I_2 iodine + Na_2CO_3 soda ash + CH_3CH_2OH ethanol ⟶ NaI sodium iodide + H_2CO_3 carbonic acid + CHI_3 iodoform + HCOONa sodium formate
I_2 iodine + Na_2CO_3 soda ash + CH_3CH_2OH ethanol ⟶ NaI sodium iodide + H_2CO_3 carbonic acid + CHI_3 iodoform + HCOONa sodium formate

Balanced equation

Balance the chemical equation algebraically: I_2 + Na_2CO_3 + CH_3CH_2OH ⟶ NaI + H_2CO_3 + CHI_3 + HCOONa Add stoichiometric coefficients, c_i, to the reactants and products: c_1 I_2 + c_2 Na_2CO_3 + c_3 CH_3CH_2OH ⟶ c_4 NaI + c_5 H_2CO_3 + c_6 CHI_3 + c_7 HCOONa Set the number of atoms in the reactants equal to the number of atoms in the products for I, C, Na, O and H: I: | 2 c_1 = c_4 + 3 c_6 C: | c_2 + 2 c_3 = c_5 + c_6 + c_7 Na: | 2 c_2 = c_4 + c_7 O: | 3 c_2 + c_3 = 3 c_5 + 2 c_7 H: | 6 c_3 = 2 c_5 + c_6 + c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_2 = 4 - c_1/2 c_3 = 1 c_4 = c_1/2 + 3/2 c_5 = c_1/2 c_6 = c_1/2 - 1/2 c_7 = 13/2 - (3 c_1)/2 Multiply by the least common denominator, 4, to eliminate fractional coefficients: c_2 = 16 - c_1/2 c_3 = 4 c_4 = c_1/2 + 6 c_5 = c_1/2 c_6 = c_1/2 - 2 c_7 = 26 - (3 c_1)/2 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 14 and solve for the remaining coefficients: c_1 = 14 c_2 = 9 c_3 = 4 c_4 = 13 c_5 = 7 c_6 = 5 c_7 = 5 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 14 I_2 + 9 Na_2CO_3 + 4 CH_3CH_2OH ⟶ 13 NaI + 7 H_2CO_3 + 5 CHI_3 + 5 HCOONa
Balance the chemical equation algebraically: I_2 + Na_2CO_3 + CH_3CH_2OH ⟶ NaI + H_2CO_3 + CHI_3 + HCOONa Add stoichiometric coefficients, c_i, to the reactants and products: c_1 I_2 + c_2 Na_2CO_3 + c_3 CH_3CH_2OH ⟶ c_4 NaI + c_5 H_2CO_3 + c_6 CHI_3 + c_7 HCOONa Set the number of atoms in the reactants equal to the number of atoms in the products for I, C, Na, O and H: I: | 2 c_1 = c_4 + 3 c_6 C: | c_2 + 2 c_3 = c_5 + c_6 + c_7 Na: | 2 c_2 = c_4 + c_7 O: | 3 c_2 + c_3 = 3 c_5 + 2 c_7 H: | 6 c_3 = 2 c_5 + c_6 + c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_2 = 4 - c_1/2 c_3 = 1 c_4 = c_1/2 + 3/2 c_5 = c_1/2 c_6 = c_1/2 - 1/2 c_7 = 13/2 - (3 c_1)/2 Multiply by the least common denominator, 4, to eliminate fractional coefficients: c_2 = 16 - c_1/2 c_3 = 4 c_4 = c_1/2 + 6 c_5 = c_1/2 c_6 = c_1/2 - 2 c_7 = 26 - (3 c_1)/2 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 14 and solve for the remaining coefficients: c_1 = 14 c_2 = 9 c_3 = 4 c_4 = 13 c_5 = 7 c_6 = 5 c_7 = 5 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 14 I_2 + 9 Na_2CO_3 + 4 CH_3CH_2OH ⟶ 13 NaI + 7 H_2CO_3 + 5 CHI_3 + 5 HCOONa

Structures

+ + ⟶ + + +
+ + ⟶ + + +

Names

iodine + soda ash + ethanol ⟶ sodium iodide + carbonic acid + iodoform + sodium formate
iodine + soda ash + ethanol ⟶ sodium iodide + carbonic acid + iodoform + sodium formate

Equilibrium constant

Construct the equilibrium constant, K, expression for: I_2 + Na_2CO_3 + CH_3CH_2OH ⟶ NaI + H_2CO_3 + CHI_3 + HCOONa Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 14 I_2 + 9 Na_2CO_3 + 4 CH_3CH_2OH ⟶ 13 NaI + 7 H_2CO_3 + 5 CHI_3 + 5 HCOONa Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i I_2 | 14 | -14 Na_2CO_3 | 9 | -9 CH_3CH_2OH | 4 | -4 NaI | 13 | 13 H_2CO_3 | 7 | 7 CHI_3 | 5 | 5 HCOONa | 5 | 5 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression I_2 | 14 | -14 | ([I2])^(-14) Na_2CO_3 | 9 | -9 | ([Na2CO3])^(-9) CH_3CH_2OH | 4 | -4 | ([CH3CH2OH])^(-4) NaI | 13 | 13 | ([NaI])^13 H_2CO_3 | 7 | 7 | ([H2CO3])^7 CHI_3 | 5 | 5 | ([CHI3])^5 HCOONa | 5 | 5 | ([HCOONa])^5 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([I2])^(-14) ([Na2CO3])^(-9) ([CH3CH2OH])^(-4) ([NaI])^13 ([H2CO3])^7 ([CHI3])^5 ([HCOONa])^5 = (([NaI])^13 ([H2CO3])^7 ([CHI3])^5 ([HCOONa])^5)/(([I2])^14 ([Na2CO3])^9 ([CH3CH2OH])^4)
Construct the equilibrium constant, K, expression for: I_2 + Na_2CO_3 + CH_3CH_2OH ⟶ NaI + H_2CO_3 + CHI_3 + HCOONa Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 14 I_2 + 9 Na_2CO_3 + 4 CH_3CH_2OH ⟶ 13 NaI + 7 H_2CO_3 + 5 CHI_3 + 5 HCOONa Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i I_2 | 14 | -14 Na_2CO_3 | 9 | -9 CH_3CH_2OH | 4 | -4 NaI | 13 | 13 H_2CO_3 | 7 | 7 CHI_3 | 5 | 5 HCOONa | 5 | 5 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression I_2 | 14 | -14 | ([I2])^(-14) Na_2CO_3 | 9 | -9 | ([Na2CO3])^(-9) CH_3CH_2OH | 4 | -4 | ([CH3CH2OH])^(-4) NaI | 13 | 13 | ([NaI])^13 H_2CO_3 | 7 | 7 | ([H2CO3])^7 CHI_3 | 5 | 5 | ([CHI3])^5 HCOONa | 5 | 5 | ([HCOONa])^5 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([I2])^(-14) ([Na2CO3])^(-9) ([CH3CH2OH])^(-4) ([NaI])^13 ([H2CO3])^7 ([CHI3])^5 ([HCOONa])^5 = (([NaI])^13 ([H2CO3])^7 ([CHI3])^5 ([HCOONa])^5)/(([I2])^14 ([Na2CO3])^9 ([CH3CH2OH])^4)

Rate of reaction

Construct the rate of reaction expression for: I_2 + Na_2CO_3 + CH_3CH_2OH ⟶ NaI + H_2CO_3 + CHI_3 + HCOONa Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 14 I_2 + 9 Na_2CO_3 + 4 CH_3CH_2OH ⟶ 13 NaI + 7 H_2CO_3 + 5 CHI_3 + 5 HCOONa Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i I_2 | 14 | -14 Na_2CO_3 | 9 | -9 CH_3CH_2OH | 4 | -4 NaI | 13 | 13 H_2CO_3 | 7 | 7 CHI_3 | 5 | 5 HCOONa | 5 | 5 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term I_2 | 14 | -14 | -1/14 (Δ[I2])/(Δt) Na_2CO_3 | 9 | -9 | -1/9 (Δ[Na2CO3])/(Δt) CH_3CH_2OH | 4 | -4 | -1/4 (Δ[CH3CH2OH])/(Δt) NaI | 13 | 13 | 1/13 (Δ[NaI])/(Δt) H_2CO_3 | 7 | 7 | 1/7 (Δ[H2CO3])/(Δt) CHI_3 | 5 | 5 | 1/5 (Δ[CHI3])/(Δt) HCOONa | 5 | 5 | 1/5 (Δ[HCOONa])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/14 (Δ[I2])/(Δt) = -1/9 (Δ[Na2CO3])/(Δt) = -1/4 (Δ[CH3CH2OH])/(Δt) = 1/13 (Δ[NaI])/(Δt) = 1/7 (Δ[H2CO3])/(Δt) = 1/5 (Δ[CHI3])/(Δt) = 1/5 (Δ[HCOONa])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: I_2 + Na_2CO_3 + CH_3CH_2OH ⟶ NaI + H_2CO_3 + CHI_3 + HCOONa Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 14 I_2 + 9 Na_2CO_3 + 4 CH_3CH_2OH ⟶ 13 NaI + 7 H_2CO_3 + 5 CHI_3 + 5 HCOONa Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i I_2 | 14 | -14 Na_2CO_3 | 9 | -9 CH_3CH_2OH | 4 | -4 NaI | 13 | 13 H_2CO_3 | 7 | 7 CHI_3 | 5 | 5 HCOONa | 5 | 5 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term I_2 | 14 | -14 | -1/14 (Δ[I2])/(Δt) Na_2CO_3 | 9 | -9 | -1/9 (Δ[Na2CO3])/(Δt) CH_3CH_2OH | 4 | -4 | -1/4 (Δ[CH3CH2OH])/(Δt) NaI | 13 | 13 | 1/13 (Δ[NaI])/(Δt) H_2CO_3 | 7 | 7 | 1/7 (Δ[H2CO3])/(Δt) CHI_3 | 5 | 5 | 1/5 (Δ[CHI3])/(Δt) HCOONa | 5 | 5 | 1/5 (Δ[HCOONa])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/14 (Δ[I2])/(Δt) = -1/9 (Δ[Na2CO3])/(Δt) = -1/4 (Δ[CH3CH2OH])/(Δt) = 1/13 (Δ[NaI])/(Δt) = 1/7 (Δ[H2CO3])/(Δt) = 1/5 (Δ[CHI3])/(Δt) = 1/5 (Δ[HCOONa])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| iodine | soda ash | ethanol | sodium iodide | carbonic acid | iodoform | sodium formate formula | I_2 | Na_2CO_3 | CH_3CH_2OH | NaI | H_2CO_3 | CHI_3 | HCOONa Hill formula | I_2 | CNa_2O_3 | C_2H_6O | INa | CH_2O_3 | CHI_3 | CHNaO_2 name | iodine | soda ash | ethanol | sodium iodide | carbonic acid | iodoform | sodium formate IUPAC name | molecular iodine | disodium carbonate | ethanol | sodium iodide | carbonic acid | iodoform | sodium oxomethanolate
| iodine | soda ash | ethanol | sodium iodide | carbonic acid | iodoform | sodium formate formula | I_2 | Na_2CO_3 | CH_3CH_2OH | NaI | H_2CO_3 | CHI_3 | HCOONa Hill formula | I_2 | CNa_2O_3 | C_2H_6O | INa | CH_2O_3 | CHI_3 | CHNaO_2 name | iodine | soda ash | ethanol | sodium iodide | carbonic acid | iodoform | sodium formate IUPAC name | molecular iodine | disodium carbonate | ethanol | sodium iodide | carbonic acid | iodoform | sodium oxomethanolate

Random Queries

NFPA health rating of N-propanol
freezing point of holmium(III) oxide vs strontium chlorate
structure diagram of hydrogen carbonate anion vs ammonium cation
CAS number of 2,3,5,6-tetrafluoroaniline
chemical types of aluminum chloride vs nickel(II) chloride
density of ammonium disulfatonickelate(II)
van der Waals radius of period 6 elements
Zn + FeS = Fe + ZnS
formal charges of chlorine(I) cation vs lead(IV) cation
atomic number of fluorine vs krypton