Input interpretation
water + sulfur dioxide + perchloric acid ⟶ sulfuric acid + hydrogen chloride
Balanced equation
Balance the chemical equation algebraically: + + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S and Cl: H: | 2 c_1 + c_3 = 2 c_4 + c_5 O: | c_1 + 2 c_2 + 4 c_3 = 4 c_4 S: | c_2 = c_4 Cl: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 4 c_3 = 1 c_4 = 4 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + 4 + ⟶ 4 +
Structures
+ + ⟶ +
Names
water + sulfur dioxide + perchloric acid ⟶ sulfuric acid + hydrogen chloride
Chemical names and formulas
| water | sulfur dioxide | perchloric acid | sulfuric acid | hydrogen chloride Hill formula | H_2O | O_2S | ClHO_4 | H_2O_4S | ClH name | water | sulfur dioxide | perchloric acid | sulfuric acid | hydrogen chloride