H2O + CrBO3 = H3BO3 + Cr2O(OH)4

water + CrBO3 ⟶ boric acid + Cr2O(OH)4

Balance the chemical equation algebraically: + CrBO3 ⟶ + Cr2O(OH)4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 CrBO3 ⟶ c_3 + c_4 Cr2O(OH)4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Cr and B: H: | 2 c_1 = 3 c_3 + 4 c_4 O: | c_1 + 3 c_2 = 3 c_3 + 5 c_4 Cr: | c_2 = 2 c_4 B: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 5 c_2 = 2 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 5 + 2 CrBO3 ⟶ 2 + Cr2O(OH)4

+ CrBO3 ⟶ + Cr2O(OH)4

water + CrBO3 ⟶ boric acid + Cr2O(OH)4

| water | CrBO3 | boric acid | Cr2O(OH)4 formula | | CrBO3 | | Cr2O(OH)4 Hill formula | H_2O | BCrO3 | BH_3O_3 | H4Cr2O5 name | water | | boric acid |

| water | CrBO3 | boric acid | Cr2O(OH)4 molar mass | 18.015 g/mol | 110.8 g/mol | 61.83 g/mol | 188.02 g/mol phase | liquid (at STP) | | solid (at STP) | melting point | 0 °C | | 160 °C | boiling point | 99.9839 °C | | | density | 1 g/cm^3 | | | surface tension | 0.0728 N/m | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | | odor | odorless | | odorless |