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trifluoro 2 propanol

Input interpretation

1, 1, 1-trifluoro-2-propanol
1, 1, 1-trifluoro-2-propanol

Chemical names and formulas

formula | CF_3CH(OH)CH_3 Hill formula | C_3H_5F_3O name | 1, 1, 1-trifluoro-2-propanol IUPAC name | 1, 1, 1-trifluoropropan-2-ol alternate names | 1, 1, 1-trifluoroisopropanol | 1, 1, 1-trifluoropropan-2-ol | 1, 1, 1-trifluoropropanol-2 | 1-methyl-2, 2, 2-trifluoroethanol mass fractions | C (carbon) 31.6% | F (fluorine) 50% | H (hydrogen) 4.42% | O (oxygen) 14%
formula | CF_3CH(OH)CH_3 Hill formula | C_3H_5F_3O name | 1, 1, 1-trifluoro-2-propanol IUPAC name | 1, 1, 1-trifluoropropan-2-ol alternate names | 1, 1, 1-trifluoroisopropanol | 1, 1, 1-trifluoropropan-2-ol | 1, 1, 1-trifluoropropanol-2 | 1-methyl-2, 2, 2-trifluoroethanol mass fractions | C (carbon) 31.6% | F (fluorine) 50% | H (hydrogen) 4.42% | O (oxygen) 14%

Lewis structure

Draw the Lewis structure of 1, 1, 1-trifluoro-2-propanol. Start by drawing the overall structure of the molecule:  Count the total valence electrons of the carbon (n_C, val = 4), fluorine (n_F, val = 7), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms: 3 n_C, val + 3 n_F, val + 5 n_H, val + n_O, val = 44 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), fluorine (n_F, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): 3 n_C, full + 3 n_F, full + 5 n_H, full + n_O, full = 66 Subtracting these two numbers shows that 66 - 44 = 22 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 11 bonds and hence 22 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 44 - 22 = 22 electrons left to draw: Answer: |   |
Draw the Lewis structure of 1, 1, 1-trifluoro-2-propanol. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4), fluorine (n_F, val = 7), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms: 3 n_C, val + 3 n_F, val + 5 n_H, val + n_O, val = 44 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), fluorine (n_F, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): 3 n_C, full + 3 n_F, full + 5 n_H, full + n_O, full = 66 Subtracting these two numbers shows that 66 - 44 = 22 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 11 bonds and hence 22 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 44 - 22 = 22 electrons left to draw: Answer: | |

3D structure

3D structure
3D structure

Basic properties

molar mass | 114.07 g/mol phase | liquid (at STP) melting point | -52 °C boiling point | 81.5 °C density | 1.259 g/cm^3 solubility in water | soluble
molar mass | 114.07 g/mol phase | liquid (at STP) melting point | -52 °C boiling point | 81.5 °C density | 1.259 g/cm^3 solubility in water | soluble

Units

Liquid properties (at STP)

density | 1.259 g/cm^3 vapor pressure | 110 mmHg (at 25 °C) dynamic viscosity | 0.00289 Pa s (at 15 °C) refractive index | 1.316
density | 1.259 g/cm^3 vapor pressure | 110 mmHg (at 25 °C) dynamic viscosity | 0.00289 Pa s (at 15 °C) refractive index | 1.316

Units

Chemical identifiers

CAS number | 374-01-6 PubChem CID number | 9774 PubChem SID number | 24878458 SMILES identifier | CC(C(F)(F)F)O InChI identifier | InChI=1/C3H5F3O/c1-2(7)3(4, 5)6/h2, 7H, 1H3 MDL number | MFCD00014403
CAS number | 374-01-6 PubChem CID number | 9774 PubChem SID number | 24878458 SMILES identifier | CC(C(F)(F)F)O InChI identifier | InChI=1/C3H5F3O/c1-2(7)3(4, 5)6/h2, 7H, 1H3 MDL number | MFCD00014403

Safety properties

flash point | 18.33 °C
flash point | 18.33 °C
DOT numbers | 1987
DOT numbers | 1987