Search

NaOH + H2C2O4 = H2O + Na2C2O4

Input interpretation

NaOH sodium hydroxide + HO_2CCO_2H oxalic acid ⟶ H_2O water + Na_2C_2O_4 sodium oxalate
NaOH sodium hydroxide + HO_2CCO_2H oxalic acid ⟶ H_2O water + Na_2C_2O_4 sodium oxalate

Balanced equation

Balance the chemical equation algebraically: NaOH + HO_2CCO_2H ⟶ H_2O + Na_2C_2O_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 HO_2CCO_2H ⟶ c_3 H_2O + c_4 Na_2C_2O_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O and C: H: | c_1 + 2 c_2 = 2 c_3 Na: | c_1 = 2 c_4 O: | c_1 + 4 c_2 = c_3 + 4 c_4 C: | 2 c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 NaOH + HO_2CCO_2H ⟶ 2 H_2O + Na_2C_2O_4
Balance the chemical equation algebraically: NaOH + HO_2CCO_2H ⟶ H_2O + Na_2C_2O_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 HO_2CCO_2H ⟶ c_3 H_2O + c_4 Na_2C_2O_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O and C: H: | c_1 + 2 c_2 = 2 c_3 Na: | c_1 = 2 c_4 O: | c_1 + 4 c_2 = c_3 + 4 c_4 C: | 2 c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 NaOH + HO_2CCO_2H ⟶ 2 H_2O + Na_2C_2O_4

Structures

+ ⟶ +
+ ⟶ +

Names

sodium hydroxide + oxalic acid ⟶ water + sodium oxalate
sodium hydroxide + oxalic acid ⟶ water + sodium oxalate

Equilibrium constant

Construct the equilibrium constant, K, expression for: NaOH + HO_2CCO_2H ⟶ H_2O + Na_2C_2O_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 NaOH + HO_2CCO_2H ⟶ 2 H_2O + Na_2C_2O_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 2 | -2 HO_2CCO_2H | 1 | -1 H_2O | 2 | 2 Na_2C_2O_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 2 | -2 | ([NaOH])^(-2) HO_2CCO_2H | 1 | -1 | ([HO2CCO2H])^(-1) H_2O | 2 | 2 | ([H2O])^2 Na_2C_2O_4 | 1 | 1 | [Na2C2O4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-2) ([HO2CCO2H])^(-1) ([H2O])^2 [Na2C2O4] = (([H2O])^2 [Na2C2O4])/(([NaOH])^2 [HO2CCO2H])
Construct the equilibrium constant, K, expression for: NaOH + HO_2CCO_2H ⟶ H_2O + Na_2C_2O_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 NaOH + HO_2CCO_2H ⟶ 2 H_2O + Na_2C_2O_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 2 | -2 HO_2CCO_2H | 1 | -1 H_2O | 2 | 2 Na_2C_2O_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 2 | -2 | ([NaOH])^(-2) HO_2CCO_2H | 1 | -1 | ([HO2CCO2H])^(-1) H_2O | 2 | 2 | ([H2O])^2 Na_2C_2O_4 | 1 | 1 | [Na2C2O4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-2) ([HO2CCO2H])^(-1) ([H2O])^2 [Na2C2O4] = (([H2O])^2 [Na2C2O4])/(([NaOH])^2 [HO2CCO2H])

Rate of reaction

Construct the rate of reaction expression for: NaOH + HO_2CCO_2H ⟶ H_2O + Na_2C_2O_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 NaOH + HO_2CCO_2H ⟶ 2 H_2O + Na_2C_2O_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 2 | -2 HO_2CCO_2H | 1 | -1 H_2O | 2 | 2 Na_2C_2O_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 2 | -2 | -1/2 (Δ[NaOH])/(Δt) HO_2CCO_2H | 1 | -1 | -(Δ[HO2CCO2H])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) Na_2C_2O_4 | 1 | 1 | (Δ[Na2C2O4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[NaOH])/(Δt) = -(Δ[HO2CCO2H])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[Na2C2O4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: NaOH + HO_2CCO_2H ⟶ H_2O + Na_2C_2O_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 NaOH + HO_2CCO_2H ⟶ 2 H_2O + Na_2C_2O_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 2 | -2 HO_2CCO_2H | 1 | -1 H_2O | 2 | 2 Na_2C_2O_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 2 | -2 | -1/2 (Δ[NaOH])/(Δt) HO_2CCO_2H | 1 | -1 | -(Δ[HO2CCO2H])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) Na_2C_2O_4 | 1 | 1 | (Δ[Na2C2O4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[NaOH])/(Δt) = -(Δ[HO2CCO2H])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[Na2C2O4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| sodium hydroxide | oxalic acid | water | sodium oxalate formula | NaOH | HO_2CCO_2H | H_2O | Na_2C_2O_4 Hill formula | HNaO | C_2H_2O_4 | H_2O | Na_2C_2O_4 name | sodium hydroxide | oxalic acid | water | sodium oxalate IUPAC name | sodium hydroxide | oxalic acid | water | disodium oxalate
| sodium hydroxide | oxalic acid | water | sodium oxalate formula | NaOH | HO_2CCO_2H | H_2O | Na_2C_2O_4 Hill formula | HNaO | C_2H_2O_4 | H_2O | Na_2C_2O_4 name | sodium hydroxide | oxalic acid | water | sodium oxalate IUPAC name | sodium hydroxide | oxalic acid | water | disodium oxalate

Substance properties

| sodium hydroxide | oxalic acid | water | sodium oxalate molar mass | 39.997 g/mol | 90.03 g/mol | 18.015 g/mol | 134 g/mol phase | solid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 323 °C | 189.5 °C | 0 °C | 260 °C boiling point | 1390 °C | 365 °C | 99.9839 °C | density | 2.13 g/cm^3 | 1.948 g/cm^3 | 1 g/cm^3 | 2.27 g/cm^3 solubility in water | soluble | | | surface tension | 0.07435 N/m | | 0.0728 N/m | dynamic viscosity | 0.004 Pa s (at 350 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |
| sodium hydroxide | oxalic acid | water | sodium oxalate molar mass | 39.997 g/mol | 90.03 g/mol | 18.015 g/mol | 134 g/mol phase | solid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 323 °C | 189.5 °C | 0 °C | 260 °C boiling point | 1390 °C | 365 °C | 99.9839 °C | density | 2.13 g/cm^3 | 1.948 g/cm^3 | 1 g/cm^3 | 2.27 g/cm^3 solubility in water | soluble | | | surface tension | 0.07435 N/m | | 0.0728 N/m | dynamic viscosity | 0.004 Pa s (at 350 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units

Random Queries

phase of tetradecanoyl chloride
solubility of chloropentafluoroethane
longest straight chain length of potassium fluoride
chemical types of titanium(III) sulfate
net ionic charge of aluminum cation vs sodium cation
IUPAC name of sulfurous acid
PubChem SID number of choline ion
chemical types of zirconium(IV) hydrogenphosphate
chemical types lutetium fluoride
H2O + O2 + Mn(OH)2 = Mn(OH)4