Input interpretation
2-(methylthio)phenylzinc iodide | molar mass
Result
Find the molar mass, M, for 2-(methylthio)phenylzinc iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3SC_6H_4ZnI Use the chemical formula, CH_3SC_6H_4ZnI, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 7 H (hydrogen) | 7 I (iodine) | 1 S (sulfur) | 1 Zn (zinc) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 7 | 12.011 H (hydrogen) | 7 | 1.008 I (iodine) | 1 | 126.90447 S (sulfur) | 1 | 32.06 Zn (zinc) | 1 | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38 M = 84.077 g/mol + 7.056 g/mol + 126.90447 g/mol + 32.06 g/mol + 65.38 g/mol = 315.48 g/mol
Unit conversion
0.3155 kg/mol (kilograms per mole)
Comparisons
≈ 0.44 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5.2×10^-22 grams | 5.2×10^-25 kg (kilograms) | 315 u (unified atomic mass units) | 315 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 315