H2 + K = KH

hydrogen + potassium ⟶ potassium hydride

Balance the chemical equation algebraically: + ⟶ Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H and K: H: | 2 c_1 = c_3 K: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | + 2 ⟶ 2

+ ⟶

hydrogen + potassium ⟶ potassium hydride

| hydrogen | potassium | potassium hydride Hill formula | H_2 | K | HK name | hydrogen | potassium | potassium hydride IUPAC name | molecular hydrogen | potassium | potassium hydride

| hydrogen | potassium | potassium hydride molar mass | 2.016 g/mol | 39.0983 g/mol | 40.106 g/mol phase | gas (at STP) | solid (at STP) | liquid (at STP) melting point | -259.2 °C | 64 °C | boiling point | -252.8 °C | 760 °C | 316 °C density | 8.99×10^-5 g/cm^3 (at 0 °C) | 0.86 g/cm^3 | 1.47 g/cm^3 solubility in water | | reacts | dynamic viscosity | 8.9×10^-6 Pa s (at 25 °C) | | odor | odorless | |