Input interpretation
etomidate | molecular mass
Result
Find the molecular mass, m, for etomidate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_14H_16N_2O_2 Use the chemical formula, C_14H_16N_2O_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 14 H (hydrogen) | 16 N (nitrogen) | 2 O (oxygen) | 2 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 14 | 12.011 H (hydrogen) | 16 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154 H (hydrogen) | 16 | 1.008 | 16 × 1.008 = 16.128 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 m = 168.154 u + 16.128 u + 28.014 u + 31.998 u = 244.294 u
Unit conversions
244.29 Da (daltons)
0.24429 kDa (kilodaltons)
4.0566×10^-22 grams
4.0566×10^-25 kg (kilograms)
244.3 chemical atomic mass units (unit officially deprecated)
244.37 physical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
≈ 0.34 × molecular mass of fullerene ( ≈ 721 u )
≈ 1.3 × molecular mass of caffeine ( ≈ 194 u )
≈ 4.2 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 244
Molar mass M from M = m_aN_A: | 244 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 244
Molar mass M from M = m_mN_A: | 244 g/mol (grams per mole)