Input interpretation
![5-bromo-2-methoxyphenylboronic acid | molar mass](../image_source/fed2d5f6b8dc911e02179a67901548e1.png)
5-bromo-2-methoxyphenylboronic acid | molar mass
Result
![Find the molar mass, M, for 5-bromo-2-methoxyphenylboronic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BrC_6H_3(OCH_3)B(OH)_2 Use the chemical formula, BrC_6H_3(OCH_3)B(OH)_2, to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 Br (bromine) | 1 C (carbon) | 7 H (hydrogen) | 8 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 Br (bromine) | 1 | 79.904 C (carbon) | 7 | 12.011 H (hydrogen) | 8 | 1.008 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 10.81 g/mol + 79.904 g/mol + 84.077 g/mol + 8.064 g/mol + 47.997 g/mol = 230.85 g/mol](../image_source/f6a1c54d546ba7f7c6450542ad5f4264.png)
Find the molar mass, M, for 5-bromo-2-methoxyphenylboronic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BrC_6H_3(OCH_3)B(OH)_2 Use the chemical formula, BrC_6H_3(OCH_3)B(OH)_2, to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 Br (bromine) | 1 C (carbon) | 7 H (hydrogen) | 8 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 Br (bromine) | 1 | 79.904 C (carbon) | 7 | 12.011 H (hydrogen) | 8 | 1.008 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 10.81 g/mol + 79.904 g/mol + 84.077 g/mol + 8.064 g/mol + 47.997 g/mol = 230.85 g/mol
Unit conversion
![0.23085 kg/mol (kilograms per mole)](../image_source/f7bb2f062aacc30ccb4e907ef913154c.png)
0.23085 kg/mol (kilograms per mole)
Comparisons
![≈ 0.32 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/860ee88a0f849f2eccd46cec4d9a0e32.png)
≈ 0.32 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/17e60ee53659c807ae01ecf8e8ee7985.png)
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/342ed69867ad8ec544523fbf6d960625.png)
≈ 4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.8×10^-22 grams | 3.8×10^-25 kg (kilograms) | 231 u (unified atomic mass units) | 231 Da (daltons)](../image_source/aa7a3dd44547c57d089d94c5417d6736.png)
Mass of a molecule m from m = M/N_A: | 3.8×10^-22 grams | 3.8×10^-25 kg (kilograms) | 231 u (unified atomic mass units) | 231 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 231](../image_source/516d20e3e1ff12c8c808295bccc92cd6.png)
Relative molecular mass M_r from M_r = M_u/M: | 231