Input interpretation
water + HClO3 + tellurium ⟶ chlorine + telluric(VI) acid
Balanced equation
Balance the chemical equation algebraically: + HClO3 + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 HClO3 + c_3 ⟶ c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Cl and Te: H: | 2 c_1 + c_2 = 6 c_5 O: | c_1 + 3 c_2 = 6 c_5 Cl: | c_2 = 2 c_4 Te: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 2 c_3 = 5/3 c_4 = 1 c_5 = 5/3 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 12 c_2 = 6 c_3 = 5 c_4 = 3 c_5 = 5 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 12 + 6 HClO3 + 5 ⟶ 3 + 5
Structures
+ HClO3 + ⟶ +
Names
water + HClO3 + tellurium ⟶ chlorine + telluric(VI) acid
Chemical names and formulas
| water | HClO3 | tellurium | chlorine | telluric(VI) acid formula | | HClO3 | | | Hill formula | H_2O | HClO3 | Te | Cl_2 | H_6O_6Te name | water | | tellurium | chlorine | telluric(VI) acid IUPAC name | water | | tellurium | molecular chlorine |
Substance properties
| water | HClO3 | tellurium | chlorine | telluric(VI) acid molar mass | 18.015 g/mol | 84.45 g/mol | 127.6 g/mol | 70.9 g/mol | 229.64 g/mol phase | liquid (at STP) | | solid (at STP) | gas (at STP) | solid (at STP) melting point | 0 °C | | 450 °C | -101 °C | 136 °C boiling point | 99.9839 °C | | 990 °C | -34 °C | density | 1 g/cm^3 | | 6.24 g/cm^3 | 0.003214 g/cm^3 (at 0 °C) | 3.068 g/cm^3 solubility in water | | | insoluble | | surface tension | 0.0728 N/m | | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | | | odor | odorless | | | |
Units
