Input interpretation
rhodium(III) iodide | molecular mass
Result
Find the molecular mass, m, for rhodium(III) iodide: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: I_3Rh Use the chemical formula, I_3Rh, to count the number of atoms, N_i, for each element: | N_i I (iodine) | 3 Rh (rhodium) | 1 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u I (iodine) | 3 | 126.90447 Rh (rhodium) | 1 | 102.90550 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u I (iodine) | 3 | 126.90447 | 3 × 126.90447 = 380.71341 Rh (rhodium) | 1 | 102.90550 | 1 × 102.90550 = 102.90550 m = 380.71341 u + 102.90550 u = 483.61891 u
Unit conversions
483.61891 Da (daltons)
0.48361891 kDa (kilodaltons)
8.0306809×10^-22 grams
8.0306809×10^-25 kg (kilograms)
483.6397 chemical atomic mass units (unit officially deprecated)
483.77265 physical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
≈ 0.67 × molecular mass of fullerene ( ≈ 721 u )
≈ 2.5 × molecular mass of caffeine ( ≈ 194 u )
≈ 8.3 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 484
Molar mass M from M = m_aN_A: | 484 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 484
Molar mass M from M = m_mN_A: | 484 g/mol (grams per mole)