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Fe(OH)3 + KSCN = KOH + Fe(SCN)3

Input interpretation

Fe(OH)_3 iron(III) hydroxide + KSCN potassium thiocyanate ⟶ KOH potassium hydroxide + C_3N_3S_3Fe_1 iron(III) thiocyanate
Fe(OH)_3 iron(III) hydroxide + KSCN potassium thiocyanate ⟶ KOH potassium hydroxide + C_3N_3S_3Fe_1 iron(III) thiocyanate

Balanced equation

Balance the chemical equation algebraically: Fe(OH)_3 + KSCN ⟶ KOH + C_3N_3S_3Fe_1 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Fe(OH)_3 + c_2 KSCN ⟶ c_3 KOH + c_4 C_3N_3S_3Fe_1 Set the number of atoms in the reactants equal to the number of atoms in the products for Fe, H, O, C, K, N and S: Fe: | c_1 = c_4 H: | 3 c_1 = c_3 O: | 3 c_1 = c_3 C: | c_2 = 3 c_4 K: | c_2 = c_3 N: | c_2 = 3 c_4 S: | c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | Fe(OH)_3 + 3 KSCN ⟶ 3 KOH + C_3N_3S_3Fe_1
Balance the chemical equation algebraically: Fe(OH)_3 + KSCN ⟶ KOH + C_3N_3S_3Fe_1 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Fe(OH)_3 + c_2 KSCN ⟶ c_3 KOH + c_4 C_3N_3S_3Fe_1 Set the number of atoms in the reactants equal to the number of atoms in the products for Fe, H, O, C, K, N and S: Fe: | c_1 = c_4 H: | 3 c_1 = c_3 O: | 3 c_1 = c_3 C: | c_2 = 3 c_4 K: | c_2 = c_3 N: | c_2 = 3 c_4 S: | c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | Fe(OH)_3 + 3 KSCN ⟶ 3 KOH + C_3N_3S_3Fe_1

Structures

+ ⟶ +
+ ⟶ +

Names

iron(III) hydroxide + potassium thiocyanate ⟶ potassium hydroxide + iron(III) thiocyanate
iron(III) hydroxide + potassium thiocyanate ⟶ potassium hydroxide + iron(III) thiocyanate

Equilibrium constant

Construct the equilibrium constant, K, expression for: Fe(OH)_3 + KSCN ⟶ KOH + C_3N_3S_3Fe_1 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: Fe(OH)_3 + 3 KSCN ⟶ 3 KOH + C_3N_3S_3Fe_1 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe(OH)_3 | 1 | -1 KSCN | 3 | -3 KOH | 3 | 3 C_3N_3S_3Fe_1 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Fe(OH)_3 | 1 | -1 | ([Fe(OH)3])^(-1) KSCN | 3 | -3 | ([KSCN])^(-3) KOH | 3 | 3 | ([KOH])^3 C_3N_3S_3Fe_1 | 1 | 1 | [C3N3S3Fe1] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Fe(OH)3])^(-1) ([KSCN])^(-3) ([KOH])^3 [C3N3S3Fe1] = (([KOH])^3 [C3N3S3Fe1])/([Fe(OH)3] ([KSCN])^3)
Construct the equilibrium constant, K, expression for: Fe(OH)_3 + KSCN ⟶ KOH + C_3N_3S_3Fe_1 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: Fe(OH)_3 + 3 KSCN ⟶ 3 KOH + C_3N_3S_3Fe_1 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe(OH)_3 | 1 | -1 KSCN | 3 | -3 KOH | 3 | 3 C_3N_3S_3Fe_1 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Fe(OH)_3 | 1 | -1 | ([Fe(OH)3])^(-1) KSCN | 3 | -3 | ([KSCN])^(-3) KOH | 3 | 3 | ([KOH])^3 C_3N_3S_3Fe_1 | 1 | 1 | [C3N3S3Fe1] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Fe(OH)3])^(-1) ([KSCN])^(-3) ([KOH])^3 [C3N3S3Fe1] = (([KOH])^3 [C3N3S3Fe1])/([Fe(OH)3] ([KSCN])^3)

Rate of reaction

Construct the rate of reaction expression for: Fe(OH)_3 + KSCN ⟶ KOH + C_3N_3S_3Fe_1 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: Fe(OH)_3 + 3 KSCN ⟶ 3 KOH + C_3N_3S_3Fe_1 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe(OH)_3 | 1 | -1 KSCN | 3 | -3 KOH | 3 | 3 C_3N_3S_3Fe_1 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Fe(OH)_3 | 1 | -1 | -(Δ[Fe(OH)3])/(Δt) KSCN | 3 | -3 | -1/3 (Δ[KSCN])/(Δt) KOH | 3 | 3 | 1/3 (Δ[KOH])/(Δt) C_3N_3S_3Fe_1 | 1 | 1 | (Δ[C3N3S3Fe1])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[Fe(OH)3])/(Δt) = -1/3 (Δ[KSCN])/(Δt) = 1/3 (Δ[KOH])/(Δt) = (Δ[C3N3S3Fe1])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: Fe(OH)_3 + KSCN ⟶ KOH + C_3N_3S_3Fe_1 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: Fe(OH)_3 + 3 KSCN ⟶ 3 KOH + C_3N_3S_3Fe_1 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Fe(OH)_3 | 1 | -1 KSCN | 3 | -3 KOH | 3 | 3 C_3N_3S_3Fe_1 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Fe(OH)_3 | 1 | -1 | -(Δ[Fe(OH)3])/(Δt) KSCN | 3 | -3 | -1/3 (Δ[KSCN])/(Δt) KOH | 3 | 3 | 1/3 (Δ[KOH])/(Δt) C_3N_3S_3Fe_1 | 1 | 1 | (Δ[C3N3S3Fe1])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[Fe(OH)3])/(Δt) = -1/3 (Δ[KSCN])/(Δt) = 1/3 (Δ[KOH])/(Δt) = (Δ[C3N3S3Fe1])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| iron(III) hydroxide | potassium thiocyanate | potassium hydroxide | iron(III) thiocyanate formula | Fe(OH)_3 | KSCN | KOH | C_3N_3S_3Fe_1 Hill formula | FeH_3O_3 | CKNS | HKO | C_3FeN_3S_3 name | iron(III) hydroxide | potassium thiocyanate | potassium hydroxide | iron(III) thiocyanate IUPAC name | ferric trihydroxide | potassium isothiocyanate | potassium hydroxide | iron(3+) trithiocyanate
| iron(III) hydroxide | potassium thiocyanate | potassium hydroxide | iron(III) thiocyanate formula | Fe(OH)_3 | KSCN | KOH | C_3N_3S_3Fe_1 Hill formula | FeH_3O_3 | CKNS | HKO | C_3FeN_3S_3 name | iron(III) hydroxide | potassium thiocyanate | potassium hydroxide | iron(III) thiocyanate IUPAC name | ferric trihydroxide | potassium isothiocyanate | potassium hydroxide | iron(3+) trithiocyanate

Substance properties

| iron(III) hydroxide | potassium thiocyanate | potassium hydroxide | iron(III) thiocyanate molar mass | 106.87 g/mol | 97.18 g/mol | 56.105 g/mol | 230.1 g/mol phase | | | solid (at STP) | melting point | | | 406 °C | boiling point | | | 1327 °C | density | | 1 g/cm^3 | 2.044 g/cm^3 | solubility in water | | | soluble | dynamic viscosity | | | 0.001 Pa s (at 550 °C) | odor | | odorless | |
| iron(III) hydroxide | potassium thiocyanate | potassium hydroxide | iron(III) thiocyanate molar mass | 106.87 g/mol | 97.18 g/mol | 56.105 g/mol | 230.1 g/mol phase | | | solid (at STP) | melting point | | | 406 °C | boiling point | | | 1327 °C | density | | 1 g/cm^3 | 2.044 g/cm^3 | solubility in water | | | soluble | dynamic viscosity | | | 0.001 Pa s (at 550 °C) | odor | | odorless | |

Units

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