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volume of 12 kg of boron

Input interpretation

convert 12 kg of boron (chemical element) to volume
convert 12 kg of boron (chemical element) to volume

Results

4.878 L (liters)
4.878 L (liters)

Possible intermediate steps

Convert from kilograms into liters: 12 kg of B (boron) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 2.46 g/cm^3 (grams per cubic centimeter) at STP of B: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(2.46 g) = 4878 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (4878 cm^3)/1 × (1 mL)/(1 cm^3) = 4878 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: |   | (4878 mL)/1 × (1 L)/(1000 mL) = 4.878 L
Convert from kilograms into liters: 12 kg of B (boron) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 2.46 g/cm^3 (grams per cubic centimeter) at STP of B: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(2.46 g) = 4878 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (4878 cm^3)/1 × (1 mL)/(1 cm^3) = 4878 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: | | (4878 mL)/1 × (1 L)/(1000 mL) = 4.878 L

Unit conversions

0.004878 m^3 (cubic meters)
0.004878 m^3 (cubic meters)
4878 cm^3 (cubic centimeters)
4878 cm^3 (cubic centimeters)
10.31 pints
10.31 pints
5.155 quarts
5.155 quarts
1.289 gallons
1.289 gallons
0.1723 ft^3 (cubic feet)
0.1723 ft^3 (cubic feet)
297.7 in^3 (cubic inches)
297.7 in^3 (cubic inches)

Comparisons as volume

 ≈ (0.84 to 0.92) × volume of a soccer ball ( 5310 to 5792 cm^3 )
≈ (0.84 to 0.92) × volume of a soccer ball ( 5310 to 5792 cm^3 )
 ≈ volume of blood in a typical human ( ≈ 5 L )
≈ volume of blood in a typical human ( ≈ 5 L )
 ≈ 1.2 × volume of a American NFL football ( ≈ 259 in^3 )
≈ 1.2 × volume of a American NFL football ( ≈ 259 in^3 )

Comparisons as volume of food or beverage

 ≈ 1.6 × volume of a US size 10 can ( 105 fl oz )
≈ 1.6 × volume of a US size 10 can ( 105 fl oz )
 ≈ 2.9 × volume of a US size 5 can ( 7 cups )
≈ 2.9 × volume of a US size 5 can ( 7 cups )
 ≈ 5.2 × volume of a US size 3 can ( 4 cups )
≈ 5.2 × volume of a US size 3 can ( 4 cups )

Interpretations

volume
volume
volume of food or beverage
volume of food or beverage
capacity
capacity
section modulus
section modulus

Basic unit dimensions

[length]^3
[length]^3

Corresponding quantities

Radius r of a sphere from V = 4πr^3/3:  | 11 cm (centimeters)  | 0.35 feet  | 4.1 inches
Radius r of a sphere from V = 4πr^3/3: | 11 cm (centimeters) | 0.35 feet | 4.1 inches
Edge length a of a cube from V = a^3:  | 17 cm (centimeters)  | 0.56 feet  | 6.7 inches
Edge length a of a cube from V = a^3: | 17 cm (centimeters) | 0.56 feet | 6.7 inches
Mass m of water from m = ρ_(H_2O)V:  | 4.9 kg (kilograms)  | 11 lb (pounds)  | (assuming maximum water density ≈ 1000 kg/m^3)
Mass m of water from m = ρ_(H_2O)V: | 4.9 kg (kilograms) | 11 lb (pounds) | (assuming maximum water density ≈ 1000 kg/m^3)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O):  | 1.631×10^26 molecules  | (assuming maximum water density ≈ 1000 kg/m^3)  | (assuming molecular mass of water ≈ 18.02 u)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O): | 1.631×10^26 molecules | (assuming maximum water density ≈ 1000 kg/m^3) | (assuming molecular mass of water ≈ 18.02 u)