Input interpretation
HCl hydrogen chloride + Sb_2S_3 antimony(III) sulfide ⟶ H_2S hydrogen sulfide + H3SbCl6
Balanced equation
Balance the chemical equation algebraically: HCl + Sb_2S_3 ⟶ H_2S + H3SbCl6 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HCl + c_2 Sb_2S_3 ⟶ c_3 H_2S + c_4 H3SbCl6 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, S and Sb: Cl: | c_1 = 6 c_4 H: | c_1 = 2 c_3 + 3 c_4 S: | 3 c_2 = c_3 Sb: | 2 c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 12 c_2 = 1 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 12 HCl + Sb_2S_3 ⟶ 3 H_2S + 2 H3SbCl6
Structures
+ ⟶ + H3SbCl6
Names
hydrogen chloride + antimony(III) sulfide ⟶ hydrogen sulfide + H3SbCl6
Equilibrium constant
Construct the equilibrium constant, K, expression for: HCl + Sb_2S_3 ⟶ H_2S + H3SbCl6 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 12 HCl + Sb_2S_3 ⟶ 3 H_2S + 2 H3SbCl6 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HCl | 12 | -12 Sb_2S_3 | 1 | -1 H_2S | 3 | 3 H3SbCl6 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HCl | 12 | -12 | ([HCl])^(-12) Sb_2S_3 | 1 | -1 | ([Sb2S3])^(-1) H_2S | 3 | 3 | ([H2S])^3 H3SbCl6 | 2 | 2 | ([H3SbCl6])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HCl])^(-12) ([Sb2S3])^(-1) ([H2S])^3 ([H3SbCl6])^2 = (([H2S])^3 ([H3SbCl6])^2)/(([HCl])^12 [Sb2S3])
Rate of reaction
Construct the rate of reaction expression for: HCl + Sb_2S_3 ⟶ H_2S + H3SbCl6 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 12 HCl + Sb_2S_3 ⟶ 3 H_2S + 2 H3SbCl6 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HCl | 12 | -12 Sb_2S_3 | 1 | -1 H_2S | 3 | 3 H3SbCl6 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HCl | 12 | -12 | -1/12 (Δ[HCl])/(Δt) Sb_2S_3 | 1 | -1 | -(Δ[Sb2S3])/(Δt) H_2S | 3 | 3 | 1/3 (Δ[H2S])/(Δt) H3SbCl6 | 2 | 2 | 1/2 (Δ[H3SbCl6])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/12 (Δ[HCl])/(Δt) = -(Δ[Sb2S3])/(Δt) = 1/3 (Δ[H2S])/(Δt) = 1/2 (Δ[H3SbCl6])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
| hydrogen chloride | antimony(III) sulfide | hydrogen sulfide | H3SbCl6 formula | HCl | Sb_2S_3 | H_2S | H3SbCl6 Hill formula | ClH | S_3Sb_2 | H_2S | H3Cl6Sb name | hydrogen chloride | antimony(III) sulfide | hydrogen sulfide | IUPAC name | hydrogen chloride | thioxo-(thioxostibanylthio)stibane | hydrogen sulfide |
Substance properties
| hydrogen chloride | antimony(III) sulfide | hydrogen sulfide | H3SbCl6 molar mass | 36.46 g/mol | 339.7 g/mol | 34.08 g/mol | 337.5 g/mol phase | gas (at STP) | solid (at STP) | gas (at STP) | melting point | -114.17 °C | 550 °C | -85 °C | boiling point | -85 °C | | -60 °C | density | 0.00149 g/cm^3 (at 25 °C) | 4.64 g/cm^3 | 0.001393 g/cm^3 (at 25 °C) | solubility in water | miscible | | | dynamic viscosity | | | 1.239×10^-5 Pa s (at 25 °C) |
Units