Input interpretation
telluric(VI) acid | molar mass
Result
Find the molar mass, M, for telluric(VI) acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_6TeO_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 6 O (oxygen) | 6 Te (tellurium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 6 | 1.008 O (oxygen) | 6 | 15.999 Te (tellurium) | 1 | 127.60 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 Te (tellurium) | 1 | 127.60 | 1 × 127.60 = 127.60 M = 6.048 g/mol + 95.994 g/mol + 127.60 g/mol = 229.64 g/mol
Unit conversion
0.22964 kg/mol (kilograms per mole)
Comparisons
≈ 0.32 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.8×10^-22 grams | 3.8×10^-25 kg (kilograms) | 230 u (unified atomic mass units) | 230 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 230