Input interpretation
lithium 4-cyclohexylbutyrate | molar mass
Result
Find the molar mass, M, for lithium 4-cyclohexylbutyrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_11(CH_2)_3CO_2Li Use the chemical formula, C_6H_11(CH_2)_3CO_2Li, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 10 H (hydrogen) | 17 Li (lithium) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 10 | 12.011 H (hydrogen) | 17 | 1.008 Li (lithium) | 1 | 6.94 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 H (hydrogen) | 17 | 1.008 | 17 × 1.008 = 17.136 Li (lithium) | 1 | 6.94 | 1 × 6.94 = 6.94 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 120.110 g/mol + 17.136 g/mol + 6.94 g/mol + 31.998 g/mol = 176.18 g/mol
Unit conversion
0.1762 kg/mol (kilograms per mole)
Comparisons
≈ ( 0.24 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.91 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 2.9×10^-22 grams | 2.9×10^-25 kg (kilograms) | 176 u (unified atomic mass units) | 176 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 176