Input interpretation
water + HClO3 + boron ⟶ hydrogen chloride + boric acid
Balanced equation
Balance the chemical equation algebraically: + HClO3 + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 HClO3 + c_3 ⟶ c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Cl and B: H: | 2 c_1 + c_2 = c_4 + 3 c_5 O: | c_1 + 3 c_2 = 3 c_5 Cl: | c_2 = c_4 B: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 2 c_4 = 1 c_5 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 + HClO3 + 2 ⟶ + 2
Structures
+ HClO3 + ⟶ +
Names
water + HClO3 + boron ⟶ hydrogen chloride + boric acid
Chemical names and formulas
| water | HClO3 | boron | hydrogen chloride | boric acid formula | | HClO3 | | | Hill formula | H_2O | HClO3 | B | ClH | BH_3O_3 name | water | | boron | hydrogen chloride | boric acid