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NaOH + Fe(NO3)3 = NaNO3 + Fe(OH)3

Input interpretation

NaOH sodium hydroxide + Fe(NO_3)_3 ferric nitrate ⟶ NaNO_3 sodium nitrate + Fe(OH)_3 iron(III) hydroxide
NaOH sodium hydroxide + Fe(NO_3)_3 ferric nitrate ⟶ NaNO_3 sodium nitrate + Fe(OH)_3 iron(III) hydroxide

Balanced equation

Balance the chemical equation algebraically: NaOH + Fe(NO_3)_3 ⟶ NaNO_3 + Fe(OH)_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 Fe(NO_3)_3 ⟶ c_3 NaNO_3 + c_4 Fe(OH)_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O, Fe and N: H: | c_1 = 3 c_4 Na: | c_1 = c_3 O: | c_1 + 9 c_2 = 3 c_3 + 3 c_4 Fe: | c_2 = c_4 N: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 NaOH + Fe(NO_3)_3 ⟶ 3 NaNO_3 + Fe(OH)_3
Balance the chemical equation algebraically: NaOH + Fe(NO_3)_3 ⟶ NaNO_3 + Fe(OH)_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 Fe(NO_3)_3 ⟶ c_3 NaNO_3 + c_4 Fe(OH)_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O, Fe and N: H: | c_1 = 3 c_4 Na: | c_1 = c_3 O: | c_1 + 9 c_2 = 3 c_3 + 3 c_4 Fe: | c_2 = c_4 N: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 NaOH + Fe(NO_3)_3 ⟶ 3 NaNO_3 + Fe(OH)_3

Structures

+ ⟶ +
+ ⟶ +

Names

sodium hydroxide + ferric nitrate ⟶ sodium nitrate + iron(III) hydroxide
sodium hydroxide + ferric nitrate ⟶ sodium nitrate + iron(III) hydroxide

Equilibrium constant

Construct the equilibrium constant, K, expression for: NaOH + Fe(NO_3)_3 ⟶ NaNO_3 + Fe(OH)_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 NaOH + Fe(NO_3)_3 ⟶ 3 NaNO_3 + Fe(OH)_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 3 | -3 Fe(NO_3)_3 | 1 | -1 NaNO_3 | 3 | 3 Fe(OH)_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 3 | -3 | ([NaOH])^(-3) Fe(NO_3)_3 | 1 | -1 | ([Fe(NO3)3])^(-1) NaNO_3 | 3 | 3 | ([NaNO3])^3 Fe(OH)_3 | 1 | 1 | [Fe(OH)3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-3) ([Fe(NO3)3])^(-1) ([NaNO3])^3 [Fe(OH)3] = (([NaNO3])^3 [Fe(OH)3])/(([NaOH])^3 [Fe(NO3)3])
Construct the equilibrium constant, K, expression for: NaOH + Fe(NO_3)_3 ⟶ NaNO_3 + Fe(OH)_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 NaOH + Fe(NO_3)_3 ⟶ 3 NaNO_3 + Fe(OH)_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 3 | -3 Fe(NO_3)_3 | 1 | -1 NaNO_3 | 3 | 3 Fe(OH)_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 3 | -3 | ([NaOH])^(-3) Fe(NO_3)_3 | 1 | -1 | ([Fe(NO3)3])^(-1) NaNO_3 | 3 | 3 | ([NaNO3])^3 Fe(OH)_3 | 1 | 1 | [Fe(OH)3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-3) ([Fe(NO3)3])^(-1) ([NaNO3])^3 [Fe(OH)3] = (([NaNO3])^3 [Fe(OH)3])/(([NaOH])^3 [Fe(NO3)3])

Rate of reaction

Construct the rate of reaction expression for: NaOH + Fe(NO_3)_3 ⟶ NaNO_3 + Fe(OH)_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 NaOH + Fe(NO_3)_3 ⟶ 3 NaNO_3 + Fe(OH)_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 3 | -3 Fe(NO_3)_3 | 1 | -1 NaNO_3 | 3 | 3 Fe(OH)_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 3 | -3 | -1/3 (Δ[NaOH])/(Δt) Fe(NO_3)_3 | 1 | -1 | -(Δ[Fe(NO3)3])/(Δt) NaNO_3 | 3 | 3 | 1/3 (Δ[NaNO3])/(Δt) Fe(OH)_3 | 1 | 1 | (Δ[Fe(OH)3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[NaOH])/(Δt) = -(Δ[Fe(NO3)3])/(Δt) = 1/3 (Δ[NaNO3])/(Δt) = (Δ[Fe(OH)3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: NaOH + Fe(NO_3)_3 ⟶ NaNO_3 + Fe(OH)_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 NaOH + Fe(NO_3)_3 ⟶ 3 NaNO_3 + Fe(OH)_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 3 | -3 Fe(NO_3)_3 | 1 | -1 NaNO_3 | 3 | 3 Fe(OH)_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 3 | -3 | -1/3 (Δ[NaOH])/(Δt) Fe(NO_3)_3 | 1 | -1 | -(Δ[Fe(NO3)3])/(Δt) NaNO_3 | 3 | 3 | 1/3 (Δ[NaNO3])/(Δt) Fe(OH)_3 | 1 | 1 | (Δ[Fe(OH)3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[NaOH])/(Δt) = -(Δ[Fe(NO3)3])/(Δt) = 1/3 (Δ[NaNO3])/(Δt) = (Δ[Fe(OH)3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| sodium hydroxide | ferric nitrate | sodium nitrate | iron(III) hydroxide formula | NaOH | Fe(NO_3)_3 | NaNO_3 | Fe(OH)_3 Hill formula | HNaO | FeN_3O_9 | NNaO_3 | FeH_3O_3 name | sodium hydroxide | ferric nitrate | sodium nitrate | iron(III) hydroxide IUPAC name | sodium hydroxide | iron(+3) cation trinitrate | sodium nitrate | ferric trihydroxide
| sodium hydroxide | ferric nitrate | sodium nitrate | iron(III) hydroxide formula | NaOH | Fe(NO_3)_3 | NaNO_3 | Fe(OH)_3 Hill formula | HNaO | FeN_3O_9 | NNaO_3 | FeH_3O_3 name | sodium hydroxide | ferric nitrate | sodium nitrate | iron(III) hydroxide IUPAC name | sodium hydroxide | iron(+3) cation trinitrate | sodium nitrate | ferric trihydroxide

Substance properties

| sodium hydroxide | ferric nitrate | sodium nitrate | iron(III) hydroxide molar mass | 39.997 g/mol | 241.86 g/mol | 84.994 g/mol | 106.87 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | melting point | 323 °C | 35 °C | 306 °C | boiling point | 1390 °C | | | density | 2.13 g/cm^3 | 1.7 g/cm^3 | 2.26 g/cm^3 | solubility in water | soluble | very soluble | soluble | surface tension | 0.07435 N/m | | | dynamic viscosity | 0.004 Pa s (at 350 °C) | | 0.003 Pa s (at 250 °C) |
| sodium hydroxide | ferric nitrate | sodium nitrate | iron(III) hydroxide molar mass | 39.997 g/mol | 241.86 g/mol | 84.994 g/mol | 106.87 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | melting point | 323 °C | 35 °C | 306 °C | boiling point | 1390 °C | | | density | 2.13 g/cm^3 | 1.7 g/cm^3 | 2.26 g/cm^3 | solubility in water | soluble | very soluble | soluble | surface tension | 0.07435 N/m | | | dynamic viscosity | 0.004 Pa s (at 350 °C) | | 0.003 Pa s (at 250 °C) |

Units

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