Input interpretation
n-acetylmuramoyl-L-alanyl-D-glutamyl-meso-2, 6-diaminoheptane-D-alanyl-D-alanine-diphosphoundecaprenol | molar mass
Result
Find the molar mass, M, for n-acetylmuramoyl-L-alanyl-D-glutamyl-meso-2, 6-diaminoheptane-D-alanyl-D-alanine-diphosphoundecaprenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_87H_143N_7O_23P_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 87 H (hydrogen) | 136 N (nitrogen) | 7 O (oxygen) | 23 P (phosphorus) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 87 | 12.011 H (hydrogen) | 136 | 1.008 N (nitrogen) | 7 | 14.007 O (oxygen) | 23 | 15.999 P (phosphorus) | 2 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 87 | 12.011 | 87 × 12.011 = 1044.957 H (hydrogen) | 136 | 1.008 | 136 × 1.008 = 137.088 N (nitrogen) | 7 | 14.007 | 7 × 14.007 = 98.049 O (oxygen) | 23 | 15.999 | 23 × 15.999 = 367.977 P (phosphorus) | 2 | 30.973761998 | 2 × 30.973761998 = 61.947523996 M = 1044.957 g/mol + 137.088 g/mol + 98.049 g/mol + 367.977 g/mol + 61.947523996 g/mol = 1710.019 g/mol
Unit conversion
1.71 kg/mol (kilograms per mole)
Comparisons
≈ 2.4 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 8.8 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 29 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 2.8×10^-21 grams | 2.8×10^-24 kg (kilograms) | 1710 u (unified atomic mass units) | 1.7 kDa (kilodaltons)
Relative molecular mass M_r from M_r = M_u/M: | 1710