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proton count of citalopram

Input interpretation

citalopram | proton count
citalopram | proton count

Result

Determine the number of protons in: citalopram (C_20H_21FN_2O) Plan: • Use the summation: N_protons = sum_i N_i Z_i. • Determine the values of N_i and Z_i. • Compute the number of protons. Use the chemical formula, C_20H_21FN_2O, to count the number of atoms, N_i, for each element:  | N_i C | 20 F | 1 H | 21 N | 2 O | 1 Look up the atomic number, Z_i, for each element in the periodic table. The number of protons per atom is equal to the atomic number:  | N_i | Z_i C | 20 | 6 F | 1 | 9 H | 21 | 1 N | 2 | 7 O | 1 | 8 Multiply N_i by Z_i to compute the number of protons for each element:  | N_i | Z_i | N_i Z_i C | 20 | 6 | 20 × 6 = 120 F | 1 | 9 | 1 × 9 = 9 H | 21 | 1 | 21 × 1 = 21 N | 2 | 7 | 2 × 7 = 14 O | 1 | 8 | 1 × 8 = 8 Sum the N_i Z_i terms to compute the number of protons, N_protons: Answer: |   | N_protons = 120 + 9 + 21 + 14 + 8 = 172
Determine the number of protons in: citalopram (C_20H_21FN_2O) Plan: • Use the summation: N_protons = sum_i N_i Z_i. • Determine the values of N_i and Z_i. • Compute the number of protons. Use the chemical formula, C_20H_21FN_2O, to count the number of atoms, N_i, for each element: | N_i C | 20 F | 1 H | 21 N | 2 O | 1 Look up the atomic number, Z_i, for each element in the periodic table. The number of protons per atom is equal to the atomic number: | N_i | Z_i C | 20 | 6 F | 1 | 9 H | 21 | 1 N | 2 | 7 O | 1 | 8 Multiply N_i by Z_i to compute the number of protons for each element: | N_i | Z_i | N_i Z_i C | 20 | 6 | 20 × 6 = 120 F | 1 | 9 | 1 × 9 = 9 H | 21 | 1 | 21 × 1 = 21 N | 2 | 7 | 2 × 7 = 14 O | 1 | 8 | 1 × 8 = 8 Sum the N_i Z_i terms to compute the number of protons, N_protons: Answer: | | N_protons = 120 + 9 + 21 + 14 + 8 = 172

Particle counts

atom count | 45 proton count | 172 p (protons) electron count | 172 e (electrons) net ionic charge | 0
atom count | 45 proton count | 172 p (protons) electron count | 172 e (electrons) net ionic charge | 0

Corresponding quantity

Moles of protons from n = N/N_A:  | 2.9×10^-22 mol (moles)
Moles of protons from n = N/N_A: | 2.9×10^-22 mol (moles)