Input interpretation
![IR-780 iodide | molar mass](../image_source/3c4cdbeb53e8d3159deb75cb32a4e8fb.png)
IR-780 iodide | molar mass
Result
![Find the molar mass, M, for IR-780 iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_36H_44ClIN_2 Use the chemical formula, C_36H_44ClIN_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 36 Cl (chlorine) | 1 H (hydrogen) | 44 I (iodine) | 1 N (nitrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 36 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 44 | 1.008 I (iodine) | 1 | 126.90447 N (nitrogen) | 2 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 36 | 12.011 | 36 × 12.011 = 432.396 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 44 | 1.008 | 44 × 1.008 = 44.352 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 M = 432.396 g/mol + 35.45 g/mol + 44.352 g/mol + 126.90447 g/mol + 28.014 g/mol = 667.12 g/mol](../image_source/0d384486394387998e562fe830480d28.png)
Find the molar mass, M, for IR-780 iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_36H_44ClIN_2 Use the chemical formula, C_36H_44ClIN_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 36 Cl (chlorine) | 1 H (hydrogen) | 44 I (iodine) | 1 N (nitrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 36 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 44 | 1.008 I (iodine) | 1 | 126.90447 N (nitrogen) | 2 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 36 | 12.011 | 36 × 12.011 = 432.396 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 44 | 1.008 | 44 × 1.008 = 44.352 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 M = 432.396 g/mol + 35.45 g/mol + 44.352 g/mol + 126.90447 g/mol + 28.014 g/mol = 667.12 g/mol
Unit conversion
![0.6671 kg/mol (kilograms per mole)](../image_source/9439f68f9379fe38a8a408abc92375f7.png)
0.6671 kg/mol (kilograms per mole)
Comparisons
![≈ 0.93 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/9cf35fdb263e479dcd1fc4022b1834b6.png)
≈ 0.93 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 3.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/985a522a1c9e7b4e17fd8681c2c3d194.png)
≈ 3.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 11 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/b335ea5c095219ca808e3fa668677835.png)
≈ 11 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.1×10^-21 grams | 1.1×10^-24 kg (kilograms) | 667 u (unified atomic mass units) | 667 Da (daltons)](../image_source/a26fa4f2d6f061b15e48ec40834ee17e.png)
Mass of a molecule m from m = M/N_A: | 1.1×10^-21 grams | 1.1×10^-24 kg (kilograms) | 667 u (unified atomic mass units) | 667 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 667](../image_source/02dd119534c7c4613a7011f6e465a04c.png)
Relative molecular mass M_r from M_r = M_u/M: | 667