Input interpretation
10-deacetylbaccatin iii | molar mass
Result
Find the molar mass, M, for 10-deacetylbaccatin iii: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_29H_36O_10 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 29 H (hydrogen) | 36 O (oxygen) | 10 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 29 | 12.011 H (hydrogen) | 36 | 1.008 O (oxygen) | 10 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 29 | 12.011 | 29 × 12.011 = 348.319 H (hydrogen) | 36 | 1.008 | 36 × 1.008 = 36.288 O (oxygen) | 10 | 15.999 | 10 × 15.999 = 159.990 M = 348.319 g/mol + 36.288 g/mol + 159.990 g/mol = 544.597 g/mol
Unit conversion
0.5446 kg/mol (kilograms per mole)
Comparisons
≈ 0.76 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.8 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 9.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 9×10^-22 grams | 9×10^-25 kg (kilograms) | 545 u (unified atomic mass units) | 545 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 545