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relative molecular mass of L-lysine

Input interpretation

L-lysine | relative molecular mass
L-lysine | relative molecular mass

Result

Find the relative molecular mass, M_r, for L-lysine: M_r = sum _iN_im_i/m_u Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2N(CH_2)_4CH(NH_2)CO_2H Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 6  H (hydrogen) | 14  N (nitrogen) | 2  O (oxygen) | 2 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table. Since m_i is divided by the atomic mass constant, m_u, the result is a unitless relative atomic mass:  | N_i | m_i/m_u  C (carbon) | 6 | 12.011  H (hydrogen) | 14 | 1.008  N (nitrogen) | 2 | 14.007  O (oxygen) | 2 | 15.999 Multiply N_i by m_i/m_u to compute the relative mass for each element. Then sum those values to compute the relative molecular mass, M_r: Answer: |   | | N_i | m_i/m_u | relative mass  C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066  H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112  N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014  O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998  M_r = 72.066 + 14.112 + 28.014 + 31.998 = 146.190
Find the relative molecular mass, M_r, for L-lysine: M_r = sum _iN_im_i/m_u Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2N(CH_2)_4CH(NH_2)CO_2H Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 14 N (nitrogen) | 2 O (oxygen) | 2 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table. Since m_i is divided by the atomic mass constant, m_u, the result is a unitless relative atomic mass: | N_i | m_i/m_u C (carbon) | 6 | 12.011 H (hydrogen) | 14 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i/m_u to compute the relative mass for each element. Then sum those values to compute the relative molecular mass, M_r: Answer: | | | N_i | m_i/m_u | relative mass C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M_r = 72.066 + 14.112 + 28.014 + 31.998 = 146.190

Comparisons

 ≈ ( 0.2 ≈ 1/5 ) × relative molecular mass of fullerene ( ≈ 721 )
≈ ( 0.2 ≈ 1/5 ) × relative molecular mass of fullerene ( ≈ 721 )
 ≈ 0.75 × relative molecular mass of caffeine ( ≈ 194 )
≈ 0.75 × relative molecular mass of caffeine ( ≈ 194 )
 ≈ 2.5 × relative molecular mass of sodium chloride ( ≈ 58 )
≈ 2.5 × relative molecular mass of sodium chloride ( ≈ 58 )

Corresponding quantities

Molar mass M from M = M_uM_r:  | 146 g/mol (grams per mole)
Molar mass M from M = M_uM_r: | 146 g/mol (grams per mole)
Molecular mass m from m = M_rM_u/N_A:  | 2.4×10^-22 grams  | 2.4×10^-25 kg (kilograms)
Molecular mass m from m = M_rM_u/N_A: | 2.4×10^-22 grams | 2.4×10^-25 kg (kilograms)