Input interpretation
sulfuric acid + potassium dichromate + hydrogen peroxide ⟶ water + oxygen + potassium sulfate + chromium sulfate
Balanced equation
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cr and K: H: | 2 c_1 + 2 c_3 = 2 c_4 O: | 4 c_1 + 7 c_2 + 2 c_3 = c_4 + 2 c_5 + 4 c_6 + 12 c_7 S: | c_1 = c_6 + 3 c_7 Cr: | 2 c_2 = 2 c_7 K: | 2 c_2 = 2 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_4 = c_3 + 4 c_5 = c_3/2 + 3/2 c_6 = 1 c_7 = 1 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_3 = 1 and solve for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 1 c_4 = 5 c_5 = 2 c_6 = 1 c_7 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + + ⟶ 5 + 2 + +
Structures
+ + ⟶ + + +
Names
sulfuric acid + potassium dichromate + hydrogen peroxide ⟶ water + oxygen + potassium sulfate + chromium sulfate
Chemical names and formulas
| sulfuric acid | potassium dichromate | hydrogen peroxide | water | oxygen | potassium sulfate | chromium sulfate Hill formula | H_2O_4S | Cr_2K_2O_7 | H_2O_2 | H_2O | O_2 | K_2O_4S | Cr_2O_12S_3 name | sulfuric acid | potassium dichromate | hydrogen peroxide | water | oxygen | potassium sulfate | chromium sulfate IUPAC name | sulfuric acid | dipotassium oxido-(oxido-dioxochromio)oxy-dioxochromium | hydrogen peroxide | water | molecular oxygen | dipotassium sulfate | chromium(+3) cation trisulfate