Input interpretation
sodium hydroxide + Bi(NO3)3 + Na2SnO2 ⟶ water + sodium nitrate + bismuth + sodium stannate
Balanced equation
Balance the chemical equation algebraically: + Bi(NO3)3 + Na2SnO2 ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 Bi(NO3)3 + c_3 Na2SnO2 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O, Bi, N and Sn: H: | c_1 = 2 c_4 Na: | c_1 + 2 c_3 = c_5 + 2 c_7 O: | c_1 + 9 c_2 + 2 c_3 = c_4 + 3 c_5 + 3 c_7 Bi: | c_2 = c_6 N: | 3 c_2 = c_5 Sn: | c_3 = c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3/2 c_4 = 3/2 c_5 = 3 c_6 = 1 c_7 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 6 c_2 = 2 c_3 = 3 c_4 = 3 c_5 = 6 c_6 = 2 c_7 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + 2 Bi(NO3)3 + 3 Na2SnO2 ⟶ 3 + 6 + 2 + 3
Structures
+ Bi(NO3)3 + Na2SnO2 ⟶ + + +
Names
sodium hydroxide + Bi(NO3)3 + Na2SnO2 ⟶ water + sodium nitrate + bismuth + sodium stannate
Chemical names and formulas
| sodium hydroxide | Bi(NO3)3 | Na2SnO2 | water | sodium nitrate | bismuth | sodium stannate formula | | Bi(NO3)3 | Na2SnO2 | | | | Hill formula | HNaO | BiN3O9 | Na2O2Sn | H_2O | NNaO_3 | Bi | Na_2O_3Sn name | sodium hydroxide | | | water | sodium nitrate | bismuth | sodium stannate IUPAC name | sodium hydroxide | | | water | sodium nitrate | bismuth | disodium dioxido-oxo-tin