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molar mass of 4-iodo-D-phenylalanine

Input interpretation

4-iodo-D-phenylalanine | molar mass
4-iodo-D-phenylalanine | molar mass

Result

Find the molar mass, M, for 4-iodo-D-phenylalanine: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_9H_10NO_2I Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 9  H (hydrogen) | 10  I (iodine) | 1  N (nitrogen) | 1  O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 9 | 12.011  H (hydrogen) | 10 | 1.008  I (iodine) | 1 | 126.90447  N (nitrogen) | 1 | 14.007  O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099  H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080  I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447  N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007  O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998  M = 108.099 g/mol + 10.080 g/mol + 126.90447 g/mol + 14.007 g/mol + 31.998 g/mol = 291.088 g/mol
Find the molar mass, M, for 4-iodo-D-phenylalanine: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_9H_10NO_2I Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 10 I (iodine) | 1 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 10 | 1.008 I (iodine) | 1 | 126.90447 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 108.099 g/mol + 10.080 g/mol + 126.90447 g/mol + 14.007 g/mol + 31.998 g/mol = 291.088 g/mol

Unit conversion

0.29109 kg/mol (kilograms per mole)
0.29109 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 5 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 5 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 4.8×10^-22 grams  | 4.8×10^-25 kg (kilograms)  | 291 u (unified atomic mass units)  | 291 Da (daltons)
Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 291 u (unified atomic mass units) | 291 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 291
Relative molecular mass M_r from M_r = M_u/M: | 291