Input interpretation
nitric acid + hydrogen iodide ⟶ water + nitrogen dioxide + iodic acid
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O and I: H: | c_1 + c_2 = 2 c_3 + c_5 N: | c_1 = c_4 O: | 3 c_1 = c_3 + 2 c_4 + 3 c_5 I: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 1 c_3 = 3 c_4 = 6 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + ⟶ 3 + 6 +
Structures
+ ⟶ + +
Names
nitric acid + hydrogen iodide ⟶ water + nitrogen dioxide + iodic acid
Chemical names and formulas
| nitric acid | hydrogen iodide | water | nitrogen dioxide | iodic acid Hill formula | HNO_3 | HI | H_2O | NO_2 | HIO_3 name | nitric acid | hydrogen iodide | water | nitrogen dioxide | iodic acid IUPAC name | nitric acid | hydrogen iodide | water | Nitrogen dioxide | iodic acid