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Cr2(SO4)3 + LiOH = Cr(OH)3 + Li2SO4

Input interpretation

Cr_2(SO_4)_3 chromium sulfate + LiOH lithium hydroxide ⟶ Cr(OH)3 + Li_2SO_4 lithium sulfate
Cr_2(SO_4)_3 chromium sulfate + LiOH lithium hydroxide ⟶ Cr(OH)3 + Li_2SO_4 lithium sulfate

Balanced equation

Balance the chemical equation algebraically: Cr_2(SO_4)_3 + LiOH ⟶ Cr(OH)3 + Li_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cr_2(SO_4)_3 + c_2 LiOH ⟶ c_3 Cr(OH)3 + c_4 Li_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for Cr, O, S, H and Li: Cr: | 2 c_1 = c_3 O: | 12 c_1 + c_2 = 3 c_3 + 4 c_4 S: | 3 c_1 = c_4 H: | c_2 = 3 c_3 Li: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 6 c_3 = 2 c_4 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | Cr_2(SO_4)_3 + 6 LiOH ⟶ 2 Cr(OH)3 + 3 Li_2SO_4
Balance the chemical equation algebraically: Cr_2(SO_4)_3 + LiOH ⟶ Cr(OH)3 + Li_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cr_2(SO_4)_3 + c_2 LiOH ⟶ c_3 Cr(OH)3 + c_4 Li_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for Cr, O, S, H and Li: Cr: | 2 c_1 = c_3 O: | 12 c_1 + c_2 = 3 c_3 + 4 c_4 S: | 3 c_1 = c_4 H: | c_2 = 3 c_3 Li: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 6 c_3 = 2 c_4 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | Cr_2(SO_4)_3 + 6 LiOH ⟶ 2 Cr(OH)3 + 3 Li_2SO_4

Structures

+ ⟶ Cr(OH)3 +
+ ⟶ Cr(OH)3 +

Names

chromium sulfate + lithium hydroxide ⟶ Cr(OH)3 + lithium sulfate
chromium sulfate + lithium hydroxide ⟶ Cr(OH)3 + lithium sulfate

Equilibrium constant

Construct the equilibrium constant, K, expression for: Cr_2(SO_4)_3 + LiOH ⟶ Cr(OH)3 + Li_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: Cr_2(SO_4)_3 + 6 LiOH ⟶ 2 Cr(OH)3 + 3 Li_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cr_2(SO_4)_3 | 1 | -1 LiOH | 6 | -6 Cr(OH)3 | 2 | 2 Li_2SO_4 | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cr_2(SO_4)_3 | 1 | -1 | ([Cr2(SO4)3])^(-1) LiOH | 6 | -6 | ([LiOH])^(-6) Cr(OH)3 | 2 | 2 | ([Cr(OH)3])^2 Li_2SO_4 | 3 | 3 | ([Li2SO4])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Cr2(SO4)3])^(-1) ([LiOH])^(-6) ([Cr(OH)3])^2 ([Li2SO4])^3 = (([Cr(OH)3])^2 ([Li2SO4])^3)/([Cr2(SO4)3] ([LiOH])^6)
Construct the equilibrium constant, K, expression for: Cr_2(SO_4)_3 + LiOH ⟶ Cr(OH)3 + Li_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: Cr_2(SO_4)_3 + 6 LiOH ⟶ 2 Cr(OH)3 + 3 Li_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cr_2(SO_4)_3 | 1 | -1 LiOH | 6 | -6 Cr(OH)3 | 2 | 2 Li_2SO_4 | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cr_2(SO_4)_3 | 1 | -1 | ([Cr2(SO4)3])^(-1) LiOH | 6 | -6 | ([LiOH])^(-6) Cr(OH)3 | 2 | 2 | ([Cr(OH)3])^2 Li_2SO_4 | 3 | 3 | ([Li2SO4])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Cr2(SO4)3])^(-1) ([LiOH])^(-6) ([Cr(OH)3])^2 ([Li2SO4])^3 = (([Cr(OH)3])^2 ([Li2SO4])^3)/([Cr2(SO4)3] ([LiOH])^6)

Rate of reaction

Construct the rate of reaction expression for: Cr_2(SO_4)_3 + LiOH ⟶ Cr(OH)3 + Li_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: Cr_2(SO_4)_3 + 6 LiOH ⟶ 2 Cr(OH)3 + 3 Li_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cr_2(SO_4)_3 | 1 | -1 LiOH | 6 | -6 Cr(OH)3 | 2 | 2 Li_2SO_4 | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cr_2(SO_4)_3 | 1 | -1 | -(Δ[Cr2(SO4)3])/(Δt) LiOH | 6 | -6 | -1/6 (Δ[LiOH])/(Δt) Cr(OH)3 | 2 | 2 | 1/2 (Δ[Cr(OH)3])/(Δt) Li_2SO_4 | 3 | 3 | 1/3 (Δ[Li2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[Cr2(SO4)3])/(Δt) = -1/6 (Δ[LiOH])/(Δt) = 1/2 (Δ[Cr(OH)3])/(Δt) = 1/3 (Δ[Li2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: Cr_2(SO_4)_3 + LiOH ⟶ Cr(OH)3 + Li_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: Cr_2(SO_4)_3 + 6 LiOH ⟶ 2 Cr(OH)3 + 3 Li_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cr_2(SO_4)_3 | 1 | -1 LiOH | 6 | -6 Cr(OH)3 | 2 | 2 Li_2SO_4 | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cr_2(SO_4)_3 | 1 | -1 | -(Δ[Cr2(SO4)3])/(Δt) LiOH | 6 | -6 | -1/6 (Δ[LiOH])/(Δt) Cr(OH)3 | 2 | 2 | 1/2 (Δ[Cr(OH)3])/(Δt) Li_2SO_4 | 3 | 3 | 1/3 (Δ[Li2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[Cr2(SO4)3])/(Δt) = -1/6 (Δ[LiOH])/(Δt) = 1/2 (Δ[Cr(OH)3])/(Δt) = 1/3 (Δ[Li2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| chromium sulfate | lithium hydroxide | Cr(OH)3 | lithium sulfate formula | Cr_2(SO_4)_3 | LiOH | Cr(OH)3 | Li_2SO_4 Hill formula | Cr_2O_12S_3 | HLiO | H3CrO3 | Li_2O_4S name | chromium sulfate | lithium hydroxide | | lithium sulfate IUPAC name | chromium(+3) cation trisulfate | lithium hydroxide | | dilithium sulfate
| chromium sulfate | lithium hydroxide | Cr(OH)3 | lithium sulfate formula | Cr_2(SO_4)_3 | LiOH | Cr(OH)3 | Li_2SO_4 Hill formula | Cr_2O_12S_3 | HLiO | H3CrO3 | Li_2O_4S name | chromium sulfate | lithium hydroxide | | lithium sulfate IUPAC name | chromium(+3) cation trisulfate | lithium hydroxide | | dilithium sulfate

Substance properties

| chromium sulfate | lithium hydroxide | Cr(OH)3 | lithium sulfate molar mass | 392.2 g/mol | 23.95 g/mol | 103.02 g/mol | 109.9 g/mol phase | liquid (at STP) | solid (at STP) | | solid (at STP) melting point | | 462 °C | | 845 °C boiling point | 330 °C | | | 1377 °C density | 1.84 g/cm^3 | 1.46 g/cm^3 | | 2.22 g/cm^3 odor | odorless | odorless | |
| chromium sulfate | lithium hydroxide | Cr(OH)3 | lithium sulfate molar mass | 392.2 g/mol | 23.95 g/mol | 103.02 g/mol | 109.9 g/mol phase | liquid (at STP) | solid (at STP) | | solid (at STP) melting point | | 462 °C | | 845 °C boiling point | 330 °C | | | 1377 °C density | 1.84 g/cm^3 | 1.46 g/cm^3 | | 2.22 g/cm^3 odor | odorless | odorless | |

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