Input interpretation
![monofluorophosphoric acid | molar mass](../image_source/1c222953fe38fc5c744411ca399e029c.png)
monofluorophosphoric acid | molar mass
Result
![Find the molar mass, M, for monofluorophosphoric acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: FP(O)(OH)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 1 H (hydrogen) | 2 O (oxygen) | 3 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 1 | 18.998403163 H (hydrogen) | 2 | 1.008 O (oxygen) | 3 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 18.998403163 g/mol + 2.016 g/mol + 47.997 g/mol + 30.973761998 g/mol = 99.985 g/mol](../image_source/4f5327c417e08968cd5b2f65a42a3efc.png)
Find the molar mass, M, for monofluorophosphoric acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: FP(O)(OH)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 1 H (hydrogen) | 2 O (oxygen) | 3 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 1 | 18.998403163 H (hydrogen) | 2 | 1.008 O (oxygen) | 3 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 18.998403163 g/mol + 2.016 g/mol + 47.997 g/mol + 30.973761998 g/mol = 99.985 g/mol
Unit conversion
![0.099985 kg/mol (kilograms per mole)](../image_source/c494cce2a5d78e40bdf54021e4b25b8a.png)
0.099985 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/feda3ae9ae94add18dae61f5c4c11887.png)
≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.51 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/dfd0dbf920096f943b63899608bb2420.png)
≈ 0.51 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/036951349834c3ccc309234ee51a3c4d.png)
≈ 1.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 100 u (unified atomic mass units) | 100 Da (daltons)](../image_source/b960f70ff21b36ae7cff5d6f7544fd58.png)
Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 100 u (unified atomic mass units) | 100 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 100](../image_source/4e4b4788802f22edaebaa09168aef2b8.png)
Relative molecular mass M_r from M_r = M_u/M: | 100