Input interpretation
![sulfuric acid + potassium dichromate + activated charcoal ⟶ water + carbon dioxide + potassium sulfate + chromium sulfate](../image_source/4e3c53f9e10e09a881de01140febc898.png)
sulfuric acid + potassium dichromate + activated charcoal ⟶ water + carbon dioxide + potassium sulfate + chromium sulfate
Balanced equation
![Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cr, K and C: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 7 c_2 = c_4 + 2 c_5 + 4 c_6 + 12 c_7 S: | c_1 = c_6 + 3 c_7 Cr: | 2 c_2 = 2 c_7 K: | 2 c_2 = 2 c_6 C: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 3/2 c_4 = 4 c_5 = 3/2 c_6 = 1 c_7 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 8 c_2 = 2 c_3 = 3 c_4 = 8 c_5 = 3 c_6 = 2 c_7 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 8 + 2 + 3 ⟶ 8 + 3 + 2 + 2](../image_source/77b42c22ca52b23bca9f2b60957c2cd7.png)
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cr, K and C: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 7 c_2 = c_4 + 2 c_5 + 4 c_6 + 12 c_7 S: | c_1 = c_6 + 3 c_7 Cr: | 2 c_2 = 2 c_7 K: | 2 c_2 = 2 c_6 C: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 3/2 c_4 = 4 c_5 = 3/2 c_6 = 1 c_7 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 8 c_2 = 2 c_3 = 3 c_4 = 8 c_5 = 3 c_6 = 2 c_7 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 8 + 2 + 3 ⟶ 8 + 3 + 2 + 2
Structures
![+ + ⟶ + + +](../image_source/fee00a7d45193851c049dd1751e9ab1f.png)
+ + ⟶ + + +
Names
![sulfuric acid + potassium dichromate + activated charcoal ⟶ water + carbon dioxide + potassium sulfate + chromium sulfate](../image_source/d0730cb8769cf02912881babfd40501c.png)
sulfuric acid + potassium dichromate + activated charcoal ⟶ water + carbon dioxide + potassium sulfate + chromium sulfate
Chemical names and formulas
![| sulfuric acid | potassium dichromate | activated charcoal | water | carbon dioxide | potassium sulfate | chromium sulfate Hill formula | H_2O_4S | Cr_2K_2O_7 | C | H_2O | CO_2 | K_2O_4S | Cr_2O_12S_3 name | sulfuric acid | potassium dichromate | activated charcoal | water | carbon dioxide | potassium sulfate | chromium sulfate IUPAC name | sulfuric acid | dipotassium oxido-(oxido-dioxochromio)oxy-dioxochromium | carbon | water | carbon dioxide | dipotassium sulfate | chromium(+3) cation trisulfate](../image_source/ef85cd0910d4891621d87db52cb2eeda.png)
| sulfuric acid | potassium dichromate | activated charcoal | water | carbon dioxide | potassium sulfate | chromium sulfate Hill formula | H_2O_4S | Cr_2K_2O_7 | C | H_2O | CO_2 | K_2O_4S | Cr_2O_12S_3 name | sulfuric acid | potassium dichromate | activated charcoal | water | carbon dioxide | potassium sulfate | chromium sulfate IUPAC name | sulfuric acid | dipotassium oxido-(oxido-dioxochromio)oxy-dioxochromium | carbon | water | carbon dioxide | dipotassium sulfate | chromium(+3) cation trisulfate