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NH4Cl + Ba(OH)2 = H2O + NH3 + BaCl2

Input interpretation

NH_4Cl ammonium chloride + Ba(OH)_2 barium hydroxide ⟶ H_2O water + NH_3 ammonia + BaCl_2 barium chloride
NH_4Cl ammonium chloride + Ba(OH)_2 barium hydroxide ⟶ H_2O water + NH_3 ammonia + BaCl_2 barium chloride

Balanced equation

Balance the chemical equation algebraically: NH_4Cl + Ba(OH)_2 ⟶ H_2O + NH_3 + BaCl_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NH_4Cl + c_2 Ba(OH)_2 ⟶ c_3 H_2O + c_4 NH_3 + c_5 BaCl_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, N, Ba and O: Cl: | c_1 = 2 c_5 H: | 4 c_1 + 2 c_2 = 2 c_3 + 3 c_4 N: | c_1 = c_4 Ba: | c_2 = c_5 O: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 2 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 NH_4Cl + Ba(OH)_2 ⟶ 2 H_2O + 2 NH_3 + BaCl_2
Balance the chemical equation algebraically: NH_4Cl + Ba(OH)_2 ⟶ H_2O + NH_3 + BaCl_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NH_4Cl + c_2 Ba(OH)_2 ⟶ c_3 H_2O + c_4 NH_3 + c_5 BaCl_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, N, Ba and O: Cl: | c_1 = 2 c_5 H: | 4 c_1 + 2 c_2 = 2 c_3 + 3 c_4 N: | c_1 = c_4 Ba: | c_2 = c_5 O: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 2 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 NH_4Cl + Ba(OH)_2 ⟶ 2 H_2O + 2 NH_3 + BaCl_2

Structures

 + ⟶ + +
+ ⟶ + +

Names

ammonium chloride + barium hydroxide ⟶ water + ammonia + barium chloride
ammonium chloride + barium hydroxide ⟶ water + ammonia + barium chloride

Reaction thermodynamics

Enthalpy

 | ammonium chloride | barium hydroxide | water | ammonia | barium chloride molecular enthalpy | -314.4 kJ/mol | -944.7 kJ/mol | -285.8 kJ/mol | -45.9 kJ/mol | -855 kJ/mol total enthalpy | -628.8 kJ/mol | -944.7 kJ/mol | -571.7 kJ/mol | -91.8 kJ/mol | -855 kJ/mol  | H_initial = -1574 kJ/mol | | H_final = -1518 kJ/mol | |  ΔH_rxn^0 | -1518 kJ/mol - -1574 kJ/mol = 55.04 kJ/mol (endothermic) | | | |
| ammonium chloride | barium hydroxide | water | ammonia | barium chloride molecular enthalpy | -314.4 kJ/mol | -944.7 kJ/mol | -285.8 kJ/mol | -45.9 kJ/mol | -855 kJ/mol total enthalpy | -628.8 kJ/mol | -944.7 kJ/mol | -571.7 kJ/mol | -91.8 kJ/mol | -855 kJ/mol | H_initial = -1574 kJ/mol | | H_final = -1518 kJ/mol | | ΔH_rxn^0 | -1518 kJ/mol - -1574 kJ/mol = 55.04 kJ/mol (endothermic) | | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: NH_4Cl + Ba(OH)_2 ⟶ H_2O + NH_3 + BaCl_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 NH_4Cl + Ba(OH)_2 ⟶ 2 H_2O + 2 NH_3 + BaCl_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_4Cl | 2 | -2 Ba(OH)_2 | 1 | -1 H_2O | 2 | 2 NH_3 | 2 | 2 BaCl_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NH_4Cl | 2 | -2 | ([NH4Cl])^(-2) Ba(OH)_2 | 1 | -1 | ([Ba(OH)2])^(-1) H_2O | 2 | 2 | ([H2O])^2 NH_3 | 2 | 2 | ([NH3])^2 BaCl_2 | 1 | 1 | [BaCl2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([NH4Cl])^(-2) ([Ba(OH)2])^(-1) ([H2O])^2 ([NH3])^2 [BaCl2] = (([H2O])^2 ([NH3])^2 [BaCl2])/(([NH4Cl])^2 [Ba(OH)2])
Construct the equilibrium constant, K, expression for: NH_4Cl + Ba(OH)_2 ⟶ H_2O + NH_3 + BaCl_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 NH_4Cl + Ba(OH)_2 ⟶ 2 H_2O + 2 NH_3 + BaCl_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_4Cl | 2 | -2 Ba(OH)_2 | 1 | -1 H_2O | 2 | 2 NH_3 | 2 | 2 BaCl_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NH_4Cl | 2 | -2 | ([NH4Cl])^(-2) Ba(OH)_2 | 1 | -1 | ([Ba(OH)2])^(-1) H_2O | 2 | 2 | ([H2O])^2 NH_3 | 2 | 2 | ([NH3])^2 BaCl_2 | 1 | 1 | [BaCl2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NH4Cl])^(-2) ([Ba(OH)2])^(-1) ([H2O])^2 ([NH3])^2 [BaCl2] = (([H2O])^2 ([NH3])^2 [BaCl2])/(([NH4Cl])^2 [Ba(OH)2])

Rate of reaction

Construct the rate of reaction expression for: NH_4Cl + Ba(OH)_2 ⟶ H_2O + NH_3 + BaCl_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 NH_4Cl + Ba(OH)_2 ⟶ 2 H_2O + 2 NH_3 + BaCl_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_4Cl | 2 | -2 Ba(OH)_2 | 1 | -1 H_2O | 2 | 2 NH_3 | 2 | 2 BaCl_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NH_4Cl | 2 | -2 | -1/2 (Δ[NH4Cl])/(Δt) Ba(OH)_2 | 1 | -1 | -(Δ[Ba(OH)2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) NH_3 | 2 | 2 | 1/2 (Δ[NH3])/(Δt) BaCl_2 | 1 | 1 | (Δ[BaCl2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/2 (Δ[NH4Cl])/(Δt) = -(Δ[Ba(OH)2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = 1/2 (Δ[NH3])/(Δt) = (Δ[BaCl2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: NH_4Cl + Ba(OH)_2 ⟶ H_2O + NH_3 + BaCl_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 NH_4Cl + Ba(OH)_2 ⟶ 2 H_2O + 2 NH_3 + BaCl_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_4Cl | 2 | -2 Ba(OH)_2 | 1 | -1 H_2O | 2 | 2 NH_3 | 2 | 2 BaCl_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NH_4Cl | 2 | -2 | -1/2 (Δ[NH4Cl])/(Δt) Ba(OH)_2 | 1 | -1 | -(Δ[Ba(OH)2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) NH_3 | 2 | 2 | 1/2 (Δ[NH3])/(Δt) BaCl_2 | 1 | 1 | (Δ[BaCl2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[NH4Cl])/(Δt) = -(Δ[Ba(OH)2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = 1/2 (Δ[NH3])/(Δt) = (Δ[BaCl2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | ammonium chloride | barium hydroxide | water | ammonia | barium chloride formula | NH_4Cl | Ba(OH)_2 | H_2O | NH_3 | BaCl_2 Hill formula | ClH_4N | BaH_2O_2 | H_2O | H_3N | BaCl_2 name | ammonium chloride | barium hydroxide | water | ammonia | barium chloride IUPAC name | ammonium chloride | barium(+2) cation dihydroxide | water | ammonia | barium(+2) cation dichloride
| ammonium chloride | barium hydroxide | water | ammonia | barium chloride formula | NH_4Cl | Ba(OH)_2 | H_2O | NH_3 | BaCl_2 Hill formula | ClH_4N | BaH_2O_2 | H_2O | H_3N | BaCl_2 name | ammonium chloride | barium hydroxide | water | ammonia | barium chloride IUPAC name | ammonium chloride | barium(+2) cation dihydroxide | water | ammonia | barium(+2) cation dichloride

Substance properties

 | ammonium chloride | barium hydroxide | water | ammonia | barium chloride molar mass | 53.49 g/mol | 171.34 g/mol | 18.015 g/mol | 17.031 g/mol | 208.2 g/mol phase | solid (at STP) | solid (at STP) | liquid (at STP) | gas (at STP) | solid (at STP) melting point | 340 °C | 300 °C | 0 °C | -77.73 °C | 963 °C boiling point | | | 99.9839 °C | -33.33 °C |  density | 1.5256 g/cm^3 | 2.2 g/cm^3 | 1 g/cm^3 | 6.96×10^-4 g/cm^3 (at 25 °C) | 3.856 g/cm^3 solubility in water | soluble | | | |  surface tension | | | 0.0728 N/m | 0.0234 N/m |  dynamic viscosity | | | 8.9×10^-4 Pa s (at 25 °C) | 1.009×10^-5 Pa s (at 25 °C) |  odor | | | odorless | | odorless
| ammonium chloride | barium hydroxide | water | ammonia | barium chloride molar mass | 53.49 g/mol | 171.34 g/mol | 18.015 g/mol | 17.031 g/mol | 208.2 g/mol phase | solid (at STP) | solid (at STP) | liquid (at STP) | gas (at STP) | solid (at STP) melting point | 340 °C | 300 °C | 0 °C | -77.73 °C | 963 °C boiling point | | | 99.9839 °C | -33.33 °C | density | 1.5256 g/cm^3 | 2.2 g/cm^3 | 1 g/cm^3 | 6.96×10^-4 g/cm^3 (at 25 °C) | 3.856 g/cm^3 solubility in water | soluble | | | | surface tension | | | 0.0728 N/m | 0.0234 N/m | dynamic viscosity | | | 8.9×10^-4 Pa s (at 25 °C) | 1.009×10^-5 Pa s (at 25 °C) | odor | | | odorless | | odorless

Units