H2SO4 + Al = H2O + H2S + Al2(SO4)3

Input interpretation

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sulfuric acid + aluminum ⟶ water + hydrogen sulfide + aluminum sulfate

Balanced equation

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$Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S and Al: H: | 2 c_1 = 2 c_3 + 2 c_4 O: | 4 c_1 = c_3 + 12 c_5 S: | c_1 = c_4 + 3 c_5 Al: | c_2 = 2 c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 5 c_2 = 8/3 c_3 = 4 c_4 = 1 c_5 = 4/3 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 15 c_2 = 8 c_3 = 12 c_4 = 3 c_5 = 4 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 15 + 8 ⟶ 12 + 3 + 4$

Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S and Al: H: | 2 c_1 = 2 c_3 + 2 c_4 O: | 4 c_1 = c_3 + 12 c_5 S: | c_1 = c_4 + 3 c_5 Al: | c_2 = 2 c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 5 c_2 = 8/3 c_3 = 4 c_4 = 1 c_5 = 4/3 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 15 c_2 = 8 c_3 = 12 c_4 = 3 c_5 = 4 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 15 + 8 ⟶ 12 + 3 + 4