NaOH + HIO3 = H2O + NaIO3

NaOH sodium hydroxide + HIO_3 iodic acid ⟶ H_2O water + NaIO_3 sodium iodate

Balance the chemical equation algebraically: NaOH + HIO_3 ⟶ H_2O + NaIO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaOH + c_2 HIO_3 ⟶ c_3 H_2O + c_4 NaIO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O and I: H: | c_1 + c_2 = 2 c_3 Na: | c_1 = c_4 O: | c_1 + 3 c_2 = c_3 + 3 c_4 I: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | NaOH + HIO_3 ⟶ H_2O + NaIO_3

+ ⟶ +

sodium hydroxide + iodic acid ⟶ water + sodium iodate

| sodium hydroxide | iodic acid | water | sodium iodate molecular enthalpy | -425.8 kJ/mol | -230.1 kJ/mol | -285.8 kJ/mol | -481.8 kJ/mol total enthalpy | -425.8 kJ/mol | -230.1 kJ/mol | -285.8 kJ/mol | -481.8 kJ/mol | H_initial = -655.9 kJ/mol | | H_final = -767.6 kJ/mol | ΔH_rxn^0 | -767.6 kJ/mol - -655.9 kJ/mol = -111.7 kJ/mol (exothermic) | | |

Construct the equilibrium constant, K, expression for: NaOH + HIO_3 ⟶ H_2O + NaIO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: NaOH + HIO_3 ⟶ H_2O + NaIO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 1 | -1 HIO_3 | 1 | -1 H_2O | 1 | 1 NaIO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaOH | 1 | -1 | ([NaOH])^(-1) HIO_3 | 1 | -1 | ([HIO3])^(-1) H_2O | 1 | 1 | [H2O] NaIO_3 | 1 | 1 | [NaIO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaOH])^(-1) ([HIO3])^(-1) [H2O] [NaIO3] = ([H2O] [NaIO3])/([NaOH] [HIO3])

Construct the rate of reaction expression for: NaOH + HIO_3 ⟶ H_2O + NaIO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: NaOH + HIO_3 ⟶ H_2O + NaIO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaOH | 1 | -1 HIO_3 | 1 | -1 H_2O | 1 | 1 NaIO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaOH | 1 | -1 | -(Δ[NaOH])/(Δt) HIO_3 | 1 | -1 | -(Δ[HIO3])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) NaIO_3 | 1 | 1 | (Δ[NaIO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[NaOH])/(Δt) = -(Δ[HIO3])/(Δt) = (Δ[H2O])/(Δt) = (Δ[NaIO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| sodium hydroxide | iodic acid | water | sodium iodate formula | NaOH | HIO_3 | H_2O | NaIO_3 Hill formula | HNaO | HIO_3 | H_2O | INaO_3 name | sodium hydroxide | iodic acid | water | sodium iodate

| sodium hydroxide | iodic acid | water | sodium iodate molar mass | 39.997 g/mol | 175.91 g/mol | 18.015 g/mol | 197.891 g/mol phase | solid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 323 °C | 110 °C | 0 °C | 425 °C boiling point | 1390 °C | | 99.9839 °C | density | 2.13 g/cm^3 | 4.629 g/cm^3 | 1 g/cm^3 | 3.56 g/cm^3 solubility in water | soluble | very soluble | | surface tension | 0.07435 N/m | | 0.0728 N/m | dynamic viscosity | 0.004 Pa s (at 350 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |