Input interpretation
![(-)-L-carnitine | molar mass](../image_source/ac01861b8b064f908c209e632e382a20.png)
(-)-L-carnitine | molar mass
Result
![Find the molar mass, M, for (-)-L-carnitine: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_7H_15NO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 7 H (hydrogen) | 15 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 7 | 12.011 H (hydrogen) | 15 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 84.077 g/mol + 15.120 g/mol + 14.007 g/mol + 47.997 g/mol = 161.201 g/mol](../image_source/3a4597445892f603427334304d0d9975.png)
Find the molar mass, M, for (-)-L-carnitine: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_7H_15NO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 7 H (hydrogen) | 15 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 7 | 12.011 H (hydrogen) | 15 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 84.077 g/mol + 15.120 g/mol + 14.007 g/mol + 47.997 g/mol = 161.201 g/mol
Unit conversion
![0.1612 kg/mol (kilograms per mole)](../image_source/41bd51034fae50ca4ea387d9c474d937.png)
0.1612 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.22 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/66b37639eb6ffcb2b4e011fec99c84bc.png)
≈ ( 0.22 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.83 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/f3ec87ffc15296b73448215a260562c7.png)
≈ 0.83 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/6b8587ba5c459331c7166ebf901d3107.png)
≈ 2.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.7×10^-22 grams | 2.7×10^-25 kg (kilograms) | 161 u (unified atomic mass units) | 161 Da (daltons)](../image_source/cef9908e887240ef271f546cfe10d6ee.png)
Mass of a molecule m from m = M/N_A: | 2.7×10^-22 grams | 2.7×10^-25 kg (kilograms) | 161 u (unified atomic mass units) | 161 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 161](../image_source/491283743ee651958ee002de79035d02.png)
Relative molecular mass M_r from M_r = M_u/M: | 161