Input interpretation
![gallium(III) perchlorate hydrate | molar mass](../image_source/eac7761833641cf49161ca8a5f69cc66.png)
gallium(III) perchlorate hydrate | molar mass
Result
![Find the molar mass, M, for gallium(III) perchlorate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ga(CIO_4)_3·xH_2o Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 Ga (gallium) | 1 H (hydrogen) | 2 O (oxygen) | 13 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 Ga (gallium) | 1 | 69.723 H (hydrogen) | 2 | 1.008 O (oxygen) | 13 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 Ga (gallium) | 1 | 69.723 | 1 × 69.723 = 69.723 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 13 | 15.999 | 13 × 15.999 = 207.987 M = 106.35 g/mol + 69.723 g/mol + 2.016 g/mol + 207.987 g/mol = 386.08 g/mol](../image_source/ae6714232328c340c460685a9934924d.png)
Find the molar mass, M, for gallium(III) perchlorate hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ga(CIO_4)_3·xH_2o Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 Ga (gallium) | 1 H (hydrogen) | 2 O (oxygen) | 13 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 Ga (gallium) | 1 | 69.723 H (hydrogen) | 2 | 1.008 O (oxygen) | 13 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 Ga (gallium) | 1 | 69.723 | 1 × 69.723 = 69.723 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 13 | 15.999 | 13 × 15.999 = 207.987 M = 106.35 g/mol + 69.723 g/mol + 2.016 g/mol + 207.987 g/mol = 386.08 g/mol
Unit conversion
![0.3861 kg/mol (kilograms per mole)](../image_source/849d996598fe0bce47da40a150cf8d17.png)
0.3861 kg/mol (kilograms per mole)
Comparisons
![≈ 0.54 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/19c76af3a3b2dde18b5d88a4a378abd7.png)
≈ 0.54 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/3f5851f381dd883d99d15832ff8f8a50.png)
≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 6.6 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/28534d1dbbc51632dfd1dd5ec3b6dd46.png)
≈ 6.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6.4×10^-22 grams | 6.4×10^-25 kg (kilograms) | 386 u (unified atomic mass units) | 386 Da (daltons)](../image_source/064b37bd70dcc044b1b89767c6f6c9ff.png)
Mass of a molecule m from m = M/N_A: | 6.4×10^-22 grams | 6.4×10^-25 kg (kilograms) | 386 u (unified atomic mass units) | 386 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 386](../image_source/d38393069c0e416849fb077bd02d0aa8.png)
Relative molecular mass M_r from M_r = M_u/M: | 386