Input interpretation
![1, 1, 1, 3, 3, 3-hexafluoropropane | molar mass](../image_source/96bdb0fcce27b1f8ef6fe954b45286f6.png)
1, 1, 1, 3, 3, 3-hexafluoropropane | molar mass
Result
![Find the molar mass, M, for 1, 1, 1, 3, 3, 3-hexafluoropropane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_3H_2F_6 Use the chemical formula, C_3H_2F_6, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 3 F (fluorine) | 6 H (hydrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 3 | 12.011 F (fluorine) | 6 | 18.998403163 H (hydrogen) | 2 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033 F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 M = 36.033 g/mol + 113.990418978 g/mol + 2.016 g/mol = 152.039 g/mol](../image_source/17a9416bcfedf353980b8053c13e47e1.png)
Find the molar mass, M, for 1, 1, 1, 3, 3, 3-hexafluoropropane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_3H_2F_6 Use the chemical formula, C_3H_2F_6, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 3 F (fluorine) | 6 H (hydrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 3 | 12.011 F (fluorine) | 6 | 18.998403163 H (hydrogen) | 2 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033 F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 M = 36.033 g/mol + 113.990418978 g/mol + 2.016 g/mol = 152.039 g/mol
Unit conversion
![0.15204 kg/mol (kilograms per mole)](../image_source/0fa7e32ad1a2bd53d49b516fbd9e1157.png)
0.15204 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.21 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/6124728c5c9c9f195769a73f39d434a9.png)
≈ ( 0.21 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.78 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/62a788b9ad2a54293d36edf1e5e4c6db.png)
≈ 0.78 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.6 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/44929a1ff12cd4e2a15bccee3c53a618.png)
≈ 2.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.5×10^-22 grams | 2.5×10^-25 kg (kilograms) | 152 u (unified atomic mass units) | 152 Da (daltons)](../image_source/4c7aff76b6d6faeb8fd3d907a68b4f85.png)
Mass of a molecule m from m = M/N_A: | 2.5×10^-22 grams | 2.5×10^-25 kg (kilograms) | 152 u (unified atomic mass units) | 152 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 152](../image_source/6a4b3e719741f3a0bcef2584e0056d98.png)
Relative molecular mass M_r from M_r = M_u/M: | 152