Input interpretation
hydrogen bromide + bromic acid ⟶ water + bromine
Balanced equation
Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for Br, H and O: Br: | c_1 + c_2 = 2 c_4 H: | c_1 + c_2 = 2 c_3 O: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 5 c_2 = 1 c_3 = 3 c_4 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 5 + ⟶ 3 + 3
Structures
+ ⟶ +
Names
hydrogen bromide + bromic acid ⟶ water + bromine
Chemical names and formulas
| hydrogen bromide | bromic acid | water | bromine Hill formula | BrH | BrHO_3 | H_2O | Br_2 name | hydrogen bromide | bromic acid | water | bromine IUPAC name | hydrogen bromide | bromic acid | water | molecular bromine