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molar mass of lucifer yellow cH

Input interpretation

lucifer yellow cH | molar mass
lucifer yellow cH | molar mass

Result

Find the molar mass, M, for lucifer yellow cH: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_13H_9Li_2N_5O_9S_2 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 13  H (hydrogen) | 9  Li (lithium) | 2  N (nitrogen) | 5  O (oxygen) | 9  S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 13 | 12.011  H (hydrogen) | 9 | 1.008  Li (lithium) | 2 | 6.94  N (nitrogen) | 5 | 14.007  O (oxygen) | 9 | 15.999  S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 13 | 12.011 | 13 × 12.011 = 156.143  H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072  Li (lithium) | 2 | 6.94 | 2 × 6.94 = 13.88  N (nitrogen) | 5 | 14.007 | 5 × 14.007 = 70.035  O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991  S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12  M = 156.143 g/mol + 9.072 g/mol + 13.88 g/mol + 70.035 g/mol + 143.991 g/mol + 64.12 g/mol = 457.24 g/mol
Find the molar mass, M, for lucifer yellow cH: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_13H_9Li_2N_5O_9S_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 13 H (hydrogen) | 9 Li (lithium) | 2 N (nitrogen) | 5 O (oxygen) | 9 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 13 | 12.011 H (hydrogen) | 9 | 1.008 Li (lithium) | 2 | 6.94 N (nitrogen) | 5 | 14.007 O (oxygen) | 9 | 15.999 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 13 | 12.011 | 13 × 12.011 = 156.143 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 Li (lithium) | 2 | 6.94 | 2 × 6.94 = 13.88 N (nitrogen) | 5 | 14.007 | 5 × 14.007 = 70.035 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 156.143 g/mol + 9.072 g/mol + 13.88 g/mol + 70.035 g/mol + 143.991 g/mol + 64.12 g/mol = 457.24 g/mol

Unit conversion

0.4572 kg/mol (kilograms per mole)
0.4572 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.4 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.4 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 7.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 7.8 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 7.6×10^-22 grams  | 7.6×10^-25 kg (kilograms)  | 457 u (unified atomic mass units)  | 457 Da (daltons)
Mass of a molecule m from m = M/N_A: | 7.6×10^-22 grams | 7.6×10^-25 kg (kilograms) | 457 u (unified atomic mass units) | 457 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 457
Relative molecular mass M_r from M_r = M_u/M: | 457