Input interpretation
![lucifer yellow cH | molar mass](../image_source/6dd6125085c987cf827ca5f30f2f6df9.png)
lucifer yellow cH | molar mass
Result
![Find the molar mass, M, for lucifer yellow cH: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_13H_9Li_2N_5O_9S_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 13 H (hydrogen) | 9 Li (lithium) | 2 N (nitrogen) | 5 O (oxygen) | 9 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 13 | 12.011 H (hydrogen) | 9 | 1.008 Li (lithium) | 2 | 6.94 N (nitrogen) | 5 | 14.007 O (oxygen) | 9 | 15.999 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 13 | 12.011 | 13 × 12.011 = 156.143 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 Li (lithium) | 2 | 6.94 | 2 × 6.94 = 13.88 N (nitrogen) | 5 | 14.007 | 5 × 14.007 = 70.035 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 156.143 g/mol + 9.072 g/mol + 13.88 g/mol + 70.035 g/mol + 143.991 g/mol + 64.12 g/mol = 457.24 g/mol](../image_source/0fd253890fb5e3d29cb6968149ea63ba.png)
Find the molar mass, M, for lucifer yellow cH: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_13H_9Li_2N_5O_9S_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 13 H (hydrogen) | 9 Li (lithium) | 2 N (nitrogen) | 5 O (oxygen) | 9 S (sulfur) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 13 | 12.011 H (hydrogen) | 9 | 1.008 Li (lithium) | 2 | 6.94 N (nitrogen) | 5 | 14.007 O (oxygen) | 9 | 15.999 S (sulfur) | 2 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 13 | 12.011 | 13 × 12.011 = 156.143 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 Li (lithium) | 2 | 6.94 | 2 × 6.94 = 13.88 N (nitrogen) | 5 | 14.007 | 5 × 14.007 = 70.035 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 S (sulfur) | 2 | 32.06 | 2 × 32.06 = 64.12 M = 156.143 g/mol + 9.072 g/mol + 13.88 g/mol + 70.035 g/mol + 143.991 g/mol + 64.12 g/mol = 457.24 g/mol
Unit conversion
![0.4572 kg/mol (kilograms per mole)](../image_source/3dc2d80ee3963a88d3b2776529a30f15.png)
0.4572 kg/mol (kilograms per mole)
Comparisons
![≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/c928635e4d12f4d20d0c3e642a554de2.png)
≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/9fc48bb945159bec8c4bb69a773997f0.png)
≈ 2.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/d461a2fbae8763026aa00f7e3217b6ee.png)
≈ 7.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7.6×10^-22 grams | 7.6×10^-25 kg (kilograms) | 457 u (unified atomic mass units) | 457 Da (daltons)](../image_source/983e24a5400fb3bfbb6c8005e05753af.png)
Mass of a molecule m from m = M/N_A: | 7.6×10^-22 grams | 7.6×10^-25 kg (kilograms) | 457 u (unified atomic mass units) | 457 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 457](../image_source/4c70dd1300004b75c3b93d6339cf0e01.png)
Relative molecular mass M_r from M_r = M_u/M: | 457