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Mg + HBr = H2 + MgBr

Input interpretation

Mg magnesium + HBr hydrogen bromide ⟶ H_2 hydrogen + MgBr
Mg magnesium + HBr hydrogen bromide ⟶ H_2 hydrogen + MgBr

Balanced equation

Balance the chemical equation algebraically: Mg + HBr ⟶ H_2 + MgBr Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Mg + c_2 HBr ⟶ c_3 H_2 + c_4 MgBr Set the number of atoms in the reactants equal to the number of atoms in the products for Mg, Br and H: Mg: | c_1 = c_4 Br: | c_2 = c_4 H: | c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 Mg + 2 HBr ⟶ H_2 + 2 MgBr
Balance the chemical equation algebraically: Mg + HBr ⟶ H_2 + MgBr Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Mg + c_2 HBr ⟶ c_3 H_2 + c_4 MgBr Set the number of atoms in the reactants equal to the number of atoms in the products for Mg, Br and H: Mg: | c_1 = c_4 Br: | c_2 = c_4 H: | c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 Mg + 2 HBr ⟶ H_2 + 2 MgBr

Structures

 + ⟶ + MgBr
+ ⟶ + MgBr

Names

magnesium + hydrogen bromide ⟶ hydrogen + MgBr
magnesium + hydrogen bromide ⟶ hydrogen + MgBr

Equilibrium constant

Construct the equilibrium constant, K, expression for: Mg + HBr ⟶ H_2 + MgBr Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 Mg + 2 HBr ⟶ H_2 + 2 MgBr Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Mg | 2 | -2 HBr | 2 | -2 H_2 | 1 | 1 MgBr | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Mg | 2 | -2 | ([Mg])^(-2) HBr | 2 | -2 | ([HBr])^(-2) H_2 | 1 | 1 | [H2] MgBr | 2 | 2 | ([MgBr])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([Mg])^(-2) ([HBr])^(-2) [H2] ([MgBr])^2 = ([H2] ([MgBr])^2)/(([Mg])^2 ([HBr])^2)
Construct the equilibrium constant, K, expression for: Mg + HBr ⟶ H_2 + MgBr Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 Mg + 2 HBr ⟶ H_2 + 2 MgBr Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Mg | 2 | -2 HBr | 2 | -2 H_2 | 1 | 1 MgBr | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Mg | 2 | -2 | ([Mg])^(-2) HBr | 2 | -2 | ([HBr])^(-2) H_2 | 1 | 1 | [H2] MgBr | 2 | 2 | ([MgBr])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Mg])^(-2) ([HBr])^(-2) [H2] ([MgBr])^2 = ([H2] ([MgBr])^2)/(([Mg])^2 ([HBr])^2)

Rate of reaction

Construct the rate of reaction expression for: Mg + HBr ⟶ H_2 + MgBr Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 Mg + 2 HBr ⟶ H_2 + 2 MgBr Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Mg | 2 | -2 HBr | 2 | -2 H_2 | 1 | 1 MgBr | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Mg | 2 | -2 | -1/2 (Δ[Mg])/(Δt) HBr | 2 | -2 | -1/2 (Δ[HBr])/(Δt) H_2 | 1 | 1 | (Δ[H2])/(Δt) MgBr | 2 | 2 | 1/2 (Δ[MgBr])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/2 (Δ[Mg])/(Δt) = -1/2 (Δ[HBr])/(Δt) = (Δ[H2])/(Δt) = 1/2 (Δ[MgBr])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: Mg + HBr ⟶ H_2 + MgBr Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 Mg + 2 HBr ⟶ H_2 + 2 MgBr Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Mg | 2 | -2 HBr | 2 | -2 H_2 | 1 | 1 MgBr | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Mg | 2 | -2 | -1/2 (Δ[Mg])/(Δt) HBr | 2 | -2 | -1/2 (Δ[HBr])/(Δt) H_2 | 1 | 1 | (Δ[H2])/(Δt) MgBr | 2 | 2 | 1/2 (Δ[MgBr])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[Mg])/(Δt) = -1/2 (Δ[HBr])/(Δt) = (Δ[H2])/(Δt) = 1/2 (Δ[MgBr])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | magnesium | hydrogen bromide | hydrogen | MgBr formula | Mg | HBr | H_2 | MgBr Hill formula | Mg | BrH | H_2 | BrMg name | magnesium | hydrogen bromide | hydrogen |  IUPAC name | magnesium | hydrogen bromide | molecular hydrogen |
| magnesium | hydrogen bromide | hydrogen | MgBr formula | Mg | HBr | H_2 | MgBr Hill formula | Mg | BrH | H_2 | BrMg name | magnesium | hydrogen bromide | hydrogen | IUPAC name | magnesium | hydrogen bromide | molecular hydrogen |

Substance properties

 | magnesium | hydrogen bromide | hydrogen | MgBr molar mass | 24.305 g/mol | 80.912 g/mol | 2.016 g/mol | 104.21 g/mol phase | solid (at STP) | gas (at STP) | gas (at STP) |  melting point | 648 °C | -86.8 °C | -259.2 °C |  boiling point | 1090 °C | -66.38 °C | -252.8 °C |  density | 1.738 g/cm^3 | 0.003307 g/cm^3 (at 25 °C) | 8.99×10^-5 g/cm^3 (at 0 °C) |  solubility in water | reacts | miscible | |  surface tension | | 0.0271 N/m | |  dynamic viscosity | | 8.4×10^-4 Pa s (at -75 °C) | 8.9×10^-6 Pa s (at 25 °C) |  odor | | | odorless |
| magnesium | hydrogen bromide | hydrogen | MgBr molar mass | 24.305 g/mol | 80.912 g/mol | 2.016 g/mol | 104.21 g/mol phase | solid (at STP) | gas (at STP) | gas (at STP) | melting point | 648 °C | -86.8 °C | -259.2 °C | boiling point | 1090 °C | -66.38 °C | -252.8 °C | density | 1.738 g/cm^3 | 0.003307 g/cm^3 (at 25 °C) | 8.99×10^-5 g/cm^3 (at 0 °C) | solubility in water | reacts | miscible | | surface tension | | 0.0271 N/m | | dynamic viscosity | | 8.4×10^-4 Pa s (at -75 °C) | 8.9×10^-6 Pa s (at 25 °C) | odor | | | odorless |

Units